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Kisachek [45]
3 years ago
6

82.8cm measured to the nearest tenth of a cm

Mathematics
2 answers:
Digiron [165]3 years ago
6 0

Answer:

The answer is already 82.8

Step-by-step explanation:

The .8 is already to the tenth so it is 82.8

sveticcg [70]3 years ago
5 0

Answer: 83.0

Step-by-step explanation:

This is the answer because if you round it to a tenth it is 83.0 and it is closest to a cm

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HELLPPP PLEASE WILL GIVE BRAINLIEST ​
avanturin [10]

Answer:

25

Step-by-step explanation:

90-65=25

4 0
3 years ago
Alberto ran 45 kilometer on Monday. On Tuesday, he runs 910 of the distance he ran on Monday. How far did he run on Tuesday? Ent
Digiron [165]

Answer:

85.95  km

Step-by-step explanation:

Given that,

Alberto ran 45 kilometers on Monday.

On Tuesday, he runs 91% of the distance he ran on Monday.

We need to find how far did he run on Tuesday. It can be given by :

T=45+45\times \dfrac{91}{100}\\\\=85.95\ km

So, he run 85.95  km on Tuesday.

7 0
3 years ago
Is the ans i got correct?<br>the total surface area is 33.8cm² <br>​
ElenaW [278]

Given:

A prism with height 5 cm and equilateral triangular base with side 2 cm.

To find:

The total surface area of the prism.

Solution:

Area of an equilateral triangle is:

A_1=\dfrac{\sqrt{3}}{4}a^2

Where, a is the side length.

Putting a=2, we get

A_1=\dfrac{\sqrt{3}}{4}(2)^2

A_1=\dfrac{\sqrt{3}}{4}(4)

A_1=\sqrt{3}

A_1\approx \sqrt{3}

The base and top of the prism are congruent so their area must be equal.

The lateral surface area of the prism is:

LA=Ph

Where, P is the perimeter of the base and h is the height of the prism.

The lateral surface area of the prism is:

A_2=(2+2+2)5

A_2=(6)5

A_2=30

Now, the total surface area is the sum of areas of bases and lateral surface area.

A=2A_1+A_2

A=2(1.73)+30

A=3.46+30

A=33.46

Therefore, the total surface area is 33.46 cm².

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
2 years ago
How much water did all the students drink on Wednesday? Explain how you figured it out. Make sure to use complete sentences and
Nady [450]

Answer:

6.58 I could be wrong but that's pretty much it is it all students together in total?

Step-by-step explanation:

just add 1.94+0.97+1.8+1.87=6.58

7 0
3 years ago
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