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Leni [432]
3 years ago
13

Given the line -2 + 2y = 5 , find the perpendicular line that goes through (1, -3). HeLP ME PLEASEE QUICK

Mathematics
1 answer:
brilliants [131]3 years ago
4 0

Answer:

x=1

Step-by-step explanation:

Find the negative reciprocal of the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line perpendicular to  − 2 + 2 y = 5 .

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dmitriy555 [2]

Answer:

When you have two sets of data, one that represents an independent variable (X) and another that represents a dependent variable (Y) (it is a response of the first variable). A diagram called scatterplot can be generated to present the ordered pairs (X, Y) in the Cartesian plane to see how the two variables are related.

In this case the independent variable (X) is the age variable of the calf and the dependent variable (Y) is the weight of the calf.

The diagram can be seen in the attached file.

Step-by-step explanation:

3 0
3 years ago
Which of the following graphs could be the graph of the function f(x)=-0.08x(x^2-11x+18)?
MariettaO [177]

Answer:

option C

Step-by-step explanation:

f(x)=-0.08x(x^2-11x+18)

Factor the parenthesis and find out the x intercepts

(x^2-11x+18)

We find out two factors whose product is 18 and sum is -11

-9  and -2 gives us product 18

-9  -2 gives us sum -11

(x^2-11x+18) =(x-9)(x-2)

f(x)=-0.08x(x^2-11x+18)

f(x)= -0.08x(x-9)(x-2)

set f(x) =0  and solve for x

-0.08x(x-9)(x-2) =0

-0.08x =0, so x=0

x-9 = 0 , so x=9

x-2 =0 , so x=2

x intercepts are (0,0) (2,0)  and (9,0)

x intercepts are not repeating

so the graph crosses x -axis at x=0, 2,9

option C is correct

The graph is attached below4


5 0
3 years ago
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The answer to the question is -24
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2 years ago
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At what value of x does the graph of the function f(x) have a vertical asymptote?
choli [55]
It will have a vertical asymptote when the denominator approaches zero.

2x-6=0

2x=6

x=3

So the vertical asymptote is the vertical line x=3
3 0
3 years ago
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