TS=8square root of 3
SU=24
TU=16 square root of 3
SU=24
TU=16 square root of 3
Find the length x. .
2 answers:
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Answer:
The measure of the perpendicular KD is 8.72 unit .
Step-by-step explanation:
Given as :
The triangle AKM , with KD perpendicular to AM
The measure of side AK = 6 unit
The measure of side KM = 10 unit
The ∠ AKM = 93°
Let The measure of side KD = x unit
Now,
∵ KD ⊥ AM , KD divide the angle ∠ AKM equally
So, ∠ AKD = ∠
I.e ∠ AKD = ∠
∴ ∠ AKD = 46.5°
Now, Again
Cos Ф =
I.e Cos 46.5° =
I.e 0.688 =
∴ KD =
I.e KD = 8.72 unit
Hence The measure of the perpendicular KD is 8.72 unit Answer
<u>Statement </u> <u>Reason</u>
<u> </u> Given
Subtract 9 from both the sides
<u></u><u> </u> Subtracting same number will not affect equation
Simplification
Multiplying by 5 both the sides
x= 10 By simplifying both the sides
Thus we solved the equation and got x =10 as answer.
Answer:
Step-by-step explanation:
