Answer:
The nth term of the geometric sequence 7, 14, 28, ... is:
Step-by-step explanation:
Given the geometric sequence
7, 14, 28, ...
We know that a geometric sequence has a constant ratio 'r' and is defined by
where a₁ is the first term and r is the common ratio
Computing the ratios of all the adjacent terms
The ratio of all the adjacent terms is the same and equal to
now substituting r = 2 and a₁ = 7 in the nth term
Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:
Answer:
Step-by-step explanation:
You are going to integrate the following function:
(1)
furthermore, you know that:
lets call to this integral, the integral Io.
for a general form of I you have In:
furthermore you use the fact that:
by using this last expression in an iterative way you obtain the following:
(2)
with n=2s a even number
for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:
Line point L would be the midpoint of question 3.
F(x) = 3x² + 6x - 1
The graph is a parabola open upward (a= 3>0) with a minimum.
Calculate the vertex:
x = -b/2a → x = -6/(2.3) = -1. Then the axis of symmetry is x = - 1
Now to calculate the minimum, plugin the value of x:
y = 3x² + 6x - 1
y = 3(-1)² + 6(-1) -1
y= 3 - 6 -1 and y = - 4,
Ten the vertex (minimum) is at (-1,- 4)
