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MAVERICK [17]
3 years ago
14

The solutions to a certain quadratic equation are x = 4 and x = -3. Write the equation in standard form below.

Mathematics
1 answer:
Kamila [148]3 years ago
4 0

Answer:

x2 - x - 12 = 0

Step-by-step explanation:

(x - 4) (x + 3) = 0

x(x + 3) -4(x + 3) = 0

x2 + 3x -4x - 12 = 0

x2 -x -12 = 0

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Factor 2x2 + 7x + 3. <br> (2x + 2)(x + 1) <br> (2x + 3)(x + 1) (2x + 1)(x + 3)
maks197457 [2]
<h3>Answer:</h3>

(2x + 1)(x + 3)

<h3>Step-by-step explanation:</h3>

It is probably easier to try the answer choices than to try to factor the expression yourself.

(2x + 2)(x + 1) = 2x² +4x +2

(2x + 3)(x + 1) = 2x² +5x +3

(2x + 1)(x + 3) = 2x² +7x +3 . . . . . correct choice

_____

<em>Constructed solution</em>

If you want to factor this yourself, you can look for factors of "ac" that add to give "b". That is, you want factors of 2·3 = 6 that add up to give 7. You don't have to look very far.

... 6 = 1·6 = 2·3 . . . . . . the first factor pair adds to give 7

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... x(2x +1) +3(2x +1) . . . . factor each pair

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