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3 years ago

The solutions to a certain quadratic equation are x = 4 and x = -3. Write the equation in standard form below.

Mathematics

1 answer:

Kamila [148]3 years ago

4 0

Answer:

x2 - x - 12 = 0

Step-by-step explanation:

(x - 4) (x + 3) = 0

x(x + 3) -4(x + 3) = 0

x2 + 3x -4x - 12 = 0

x2 -x -12 = 0

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What is the square root of 625

QveST [7]

$De finition:\\\sqrt{a}=b\ \iff b^2=a\\=====================\\\\$

$625|5\\125|5\\.\ 25|5\\.\ \ 5|5\\.\ \ 1|\\\\625=5\times5\times5\times5=5^2\times5^2\\\\\sqrt{625}=\sqrt{5^2\times5^2}=(*)\\-------------------------------\\use:\ \sqrt{a\times b}=\sqrt{a}\times\sqrt{b}\ and\ \sqrt{a^2}=a\ for\ a\geq0\\-------------------------------\\(*)=\sqrt{5^2}\times\sqrt{5^2}=5\times5=\boxed{25}$

$Other\ solution:\\\\\sqrt{625}=25\ because\ 25^2=25\times25=625$

6 0

3 years ago

1.) Which of the following expressions is the difference of two terms?

Step2247 [10]

Answer:

1.a

2.a

3.d

4.c

5.c

Step-by-step explanation:

sana makatulung po

8 0

3 years ago

3 2. Write the equation of a line that includes the point (-4, 0) and has a slope of 5 in slope-intercept form- 12 3 y=-=X-2 5 5

Arturiano [62]

Answer:

y= 5x+20

Step-by-step explanation:

Slope intercept form is

y = mx+b where m is the slope and b is the y intercept

The slope is 5 and a point on the line is (-4,0)

Substituting this information into the equation, we can solve for b

0 = 5(-4) +b

0 = -20+b

Add 20 to each side

0+20 = -20+20+b

20 = b

y = 5x+20

8 0

2 years ago

Read 2 more answers

What is 20 - {4 + [4 + (10/2)]}

vampirchik [111]

Answer:

Step-by-step explanation:

Plugged it in the calc!

Hope it helps :)

3 0

3 years ago

Someone help? I need to get this right!

Lelechka [254]

Answer:

I think the answer is b

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers