Answer:
=(x-2)/3(x+4)
Step-by-step explanation:
F(x)=x²-3x+2/3x²+9x-12
Using mid term break formula
=x²-2x-x+2/3(x²+3x-4)
=x(x-2)-1(x-2)/3(x²+4x-x-4)
=(x-2)(x-1)/3{x(x+4)-1(x+4)}
=(x-2)(x-1)/3(x-1)(x+4)
Cancelling (x-1)
We get
=(x-2)/3(x+4)
Hope it helps :)
Answer:
Step-by-step explanation:
Answer:
it is likely that a female will be picked
Step-by-step explanation:
the probability of selecting a female = 21/25....or 84%
Answer:
![\boxed{\mathrm{view \: attachment}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cmathrm%7Bview%20%5C%3A%20attachment%7D%7D)
Step-by-step explanation:
The zeros of a function is where the function crosses the x-axis. The x-intercepts are the zeros of a function.
![f(x) = (x - 1)(x - 7)](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%28x%20-%201%29%28x%20-%207%29)
Let output equal to 0.
![0 = (x - 1)(x - 7)](https://tex.z-dn.net/?f=0%20%3D%20%28x%20-%201%29%28x%20-%207%29)
Set factors equal to 0.
![x-1=0\\x=1](https://tex.z-dn.net/?f=x-1%3D0%5C%5Cx%3D1)
![x-7=0\\x=7](https://tex.z-dn.net/?f=x-7%3D0%5C%5Cx%3D7)
The zeros of the function are
and
.
Answer:
1,333 frogs
Step-by-step explanation:
okay so we know that mass remains conserved no matter where you are.
same here ^^
if the total mass of brass is 200 kg
the total mass of the new frogs formed from it when put together will be the same :)
and if there were n such frogs formed
we have,
total mass = n × mass of each frog
200 = n × 3/ 20
n = 4000/ 3
so it becomes something like 1,333.33
that is nearly 1,333 frogs can be made out of 200 kg of brass each weighing 3/ 20kg (the last ones a bit less to make upto 200kg)