Kind of confusing....if it was 1 ten and 6 ones it'd be 16.... So with that, the answer to this would be 26
Step 1. Simplify 9^2 to 81
81 <span>÷ (-3)^0
Step 2. Use Rule of Zero: x^0 = 1
81 </span><span>÷ 1
Step 3. Simplify
81</span>
Answer:
please wait for 10 minutes I will give your answer
Answer:
The required probability is 0.55404.
Step-by-step explanation:
Consider the provided information.
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.
Average error for 7 pages booklet and 5 pages booklet series is:
λ = 0.2×7 + 0.3×5 = 2.9
According to Poisson distribution: 
Where
is average number of events.
The probability of more than 2 typographical errors in the two booklets in total is:

Substitute the respective values in the above formula.



Hence, the required probability is 0.55404.
Answer:
B and E
Step-by-step explanation:
B = - 6, D = - 2, E = 2
d(B, D) = - 2-(-6)= - 2 + 6 = 4 units
d(D, E) 2 - (-2) = 2 + 2 = 4
Since, d( B, D) = d( D, E)
Therefore, Point D is 1/2 of the distance between B and E.