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valentinak56 [21]
3 years ago
9

What is the degree of the polynomial

%2B7%60%3F" id="TexFormula1" title="`f\left(x\right)=x^{3}+5x^{4}-2x+7`?" alt="`f\left(x\right)=x^{3}+5x^{4}-2x+7`?" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
UkoKoshka [18]3 years ago
4 0
The degree of the polynomial is 4
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The Salk polio vaccine experiment in 1954 focused on the effectiveness of the vaccine in combating paralytic polio. Because it w
sdas [7]

Answer:

Step-by-step explanation:

Hello!

The variables of interest are:

X₁: Number of cases of polio observed in kids that received the placebo vaccine.

n₁= 201299 total children studied

x₁= 110 cases observed

X₂: Number of cases of polio observed in kids that received the experimental vaccine.

n₂= 200745 total children studied

x₂= 33 cases observed

These two variables have a binomial distribution. The parameters of interest, the ones to compare, are the population proportions: p₁ vs p₂

You have to test if the population proportions of children who contracted polio in both groups are different: p₂ ≠ p₁

a)

H₀: p₂ = p₁

H₁: p₂ ≠ p₁

α: 0.05

Z= \frac{(p'_2-p'_1)-(p_2-p_1)}{\sqrt{p'[\frac{1}{n_1} +\frac{1}{n_2} ]} }

Sample proportion placebo p'₁= x₁/n₁= 110/201299= 0.0005

Sample proportion vaccine p'₂= x₂/n₂= 33/200745= 0.0002

Pooled sample proportion p'= (x₁+x₂)/(n₁+n₂)= (110+33)/(201299+200745)= 0.0004

Z_{H_0}= \frac{(0.0002-0.0005)-0}{\sqrt{0.0004[\frac{1}{201299} +\frac{1}{200745} ]} }= -4.76

This test is two-tailed, using the critical value approach, you have to determine two critical values:

Z_{\alpha/2}= Z_{0.025}= -1.96

Z_{1-\alpha /2}= Z_{0.975}= 1.96

Then if Z_{H_0} ≤ -1.96 or if Z_{H_0} ≥ 1.96, the decision is to reject the null hypothesis.

If -1.96 < Z_{H_0} < 1.96, the decision is to not reject the null hypothesis.

⇒ Z_{H_0}= -4.76, the decision is to reject the null hypothesis.

b)

H₀: p₂ = p₁

H₁: p₂ ≠ p₁

α: 0.01

Z= \frac{(p'_2-p'_1)-(p_2-p_1)}{\sqrt{p'[\frac{1}{n_1} +\frac{1}{n_2} ]} }

The value of Z_{H_0}= -4.76 doesn't change, since we are working with the same samples.

The only thing that changes alongside with the level of significance is the rejection region:

Z_{\alpha /2}= Z_{0.005}= -2.576

Z_{1-\alpha /2}= Z_{0.995}= 2.576

Then if Z_{H_0} ≤ -2.576or if Z_{H_0} ≥ 2.576, the decision is to reject the null hypothesis.

If -2.576< Z_{H_0} < 2.576, the decision is to not reject the null hypothesis.

⇒ Z_{H_0}= -4.76, the decision is to reject the null hypothesis.

c)

Remember the level of significance (probability of committing type I error) is the probability of rejecting a true null hypothesis. This means that the smaller this value is, the fewer chances you have of discarding the true null hypothesis. But as you know, you cannot just reduce this value to zero because, the smaller α is, the bigger β (probability of committing type II error) becomes.

Rejecting the null hypothesis using different values of α means that there is a high chance that you reached a correct decision (rejecting a false null hypothesis)

I hope this helps!

8 0
3 years ago
Express 3360 as a product of prime factors<br> PLS HELP ME !!!!!!!!
anyanavicka [17]

Answer:

7*5*3*2^5

Step-by-step explanation:

3360/2

1680*2

840*2^2

210*2^4

105*2^5

21*5*2^5

7*5*3*2^5

7 0
3 years ago
Art Club Flyer
Finger [1]

The area of Erin's circle to the nearest hundredth is 50.24 in².

<h3>What is the area of the circle?
</h3>

A circle is a bounded figure which points from its center to its circumference is equidistant.

Area of a circle = πr²

Where :

  • π = pi = 3.14
  • R = radius

3.14 X 4²

(3.14) (4) (4) = 50.24 in²

To learn more about the area of a circle, please check: brainly.com/question/14351152

#SPJ1

8 0
1 year ago
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What is the solution to this equation? 7-1^3 √2-x=12
nydimaria [60]

What is the solution to this equation? 7-1^3 √2-x=12

X=5

7 0
2 years ago
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What is an angle that is adjacent to DEA?
White raven [17]

Answer:

CED or AEB

Step-by-step explanation:

adjacent angles share the same vertex and one side so it will be either CED or AEB

5 0
2 years ago
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