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zvonat [6]
3 years ago
11

Solve the inequality x2-x-12 < 0 +

Mathematics
2 answers:
Olin [163]3 years ago
4 0

Step-by-step explanation:

x2-x-12<0

x2-x<12

x=12

Dmitry [639]3 years ago
4 0
The answer is x= 12
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7 0
3 years ago
Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar
Brrunno [24]

The distance between the two points is d=8.6m

The polar coordinate of A is \left(4.47,296.57\right)

The polar coordinate of B is \left(4.24,135\right)

Explanation:

The two points are A(2,-4) and B(-3,3)

The distance between two points is given by,

d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6

Thus, the distance between the two points is d=8.6m

The polar coordinates of A can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting A(2,-4), we get,

Distance = \sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47

tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43

To make the angle positive, let us add 360,

\theta=360-63.43=296.57

The polar coordinate of A is \left(4.47,296.57\right)

Similarly, The polar coordinate of B can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting B(-3,3), we get,

Distance = \sqrt{(3)^{2}+(3)^{2}}=4.24

tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45

To make the angle positive, let us add 360,

\theta=180-45=135^{\circ}

The polar coordinate of B is \left(4.24,135\right)

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3 years ago
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7 0
3 years ago
Two angles in a triangle have measures of 23 and 98 what is the third measure of the third angle
Feliz [49]

Answer:

59

Step-by-step explanation:

As far as I know every triangle has to equal 180°

So if you add 98+23 you would get 121

subtract that from 180 and get 59

Hope this helps!

5 0
3 years ago
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Can you please help with this
sleet_krkn [62]

Answer:

Exercise 1 : a. 4 ; b. -4

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Step-by-step explanation:

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