Question
Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?
a)39x+30<45x+18
b) 45x+18>39x+30
c) 45x+18<39x+30
d)39x+18<45x+30
Answer:
c) 45x+18<39x+30
Step-by-step explanation:
Step 1
We have to find the Algebraic expressions for the cable companies
Cable company A charges $45 a month for cable plus a $18 installation fee.
Let the number of months be represented as x
Hence, this is represented as:
$45 × x + $18
= 45x + 18
Cable B charges $39 a month for cable plus a $30 fee for installation.
Let the number of months be represented as x
Hence, this is represented as:
$39 × x + $30
= 39x + 30
The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?
= Cable company A < Cable company B
= 45x + 18 < 39x + 30
Therefore option c is correct
Answer:
x=20
Step-by-step explanation:
x=20 because (4x+3)=77 so you take out of parnetheses
Answer:
/5.2 + 81.9 = 47.2
Step-by-step explanation:
Subtract 81.9 from both sides of the equation
Simplify
Subtract the numbers
Multiply all terms by the same value to eliminate denominators
Cancel multiplied terms that are in the denominator
Multiply the numbers
Solution: k = -180.44
<h3>
Correct Question :</h3>
Express in arithmetic :
Seven added to double a number.
<h3>
Solution :</h3>
Let the unknown be x.
Then, double of the number = 2x.
Atq,
2x+7
Hence,seven added to double a number = 2x+7
Answer:
I think they mean this thing
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