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sp2606 [1]
1 year ago
15

I need help please Asap

Mathematics
1 answer:
s2008m [1.1K]1 year ago
4 0

Answer:

Step-by-step explanation:

1.

Equation one:

x = -5, x = -1 (Both are real)

Equation two:

No real solutions

Equation three:

x = -3 (Real)

Equation four:

No real solutions

2.

The easiest way to figure out if an equation has real solutions is to factor it. If it is factorable, then it has real solutions. If it isn't, then it doesn't have real solutions.

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A factory uses 1/6 of a barrel of raisins in each batch of granola bars. Yesterday, the factory used 1/2 of a barrel of raisins.
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4 0
3 years ago
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3 years ago
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3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%E2%88%923x2%E2%88%9211x%2B7" id="TexFormula1" title="f(x) = &minus;3x2&minus
bixtya [17]

Answer:

x=   \frac{ - 11 +  \sqrt{205} }{6}  \:  \:  \:  \:  \: or \:  \:  \:  \:  \\x  =  \frac{ - 11 -  \sqrt{205} }{6}

Step-by-step explanation:

- 3x {}^{2}  - 11x + 7 = 0 \\ 3x {}^{2}  + 11x - 7 = 0

here,

a = 3 \\ b = 11 \\ c =  - 7

now,

D = b {}^{2}  - 4ac \\  = (11) {}^{2}  - 4(3)( - 7) \\  = 121 + 84 \\  = 205  > 0 \\

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4 0
2 years ago
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