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dlinn [17]
3 years ago
14

What are the solutions of the equation x4 + 95x2 – 500 = 0? Use factoring to solve.

Mathematics
2 answers:
VMariaS [17]3 years ago
8 0

Given

The equation in the form

x^{4}+95x^{2}-500 =0

Find the factor of the above equation

To proof

factoring the above equation

we get

x^{4}+100x^{2}-5x^{2}-500 =0\\\\x^{2}(x^{2}+100)-5(x^{2}+100)=0\\\\(x^{2}-5)(x^{2}+100)=0

now sloving the equation we get the value

x² = 5

x² = -100

x =\pm \sqrt{5}\\\\ x=\sqrt{-100}

The factor of the equation is

x=\pm \sqrt{5}\\\\ x= \pm 10i

Hence proved

baherus [9]3 years ago
6 0
X= the square root of 5
x= the square root of -5
x=10i
x=-10i

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If the sum of interior angle measures of a polygon is 720, how many sides does the polygon have?
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You have conducted a survey on a number of households and found out how many pets they owned brainly
eduard

Answer:

Using tally marks

Step-by-step explanation:

Missing information;

Number of pets are;

3,0,1,4,4,1,2,0,2,2,0,2,0,1,3,1,2,1,1,3

Find;

Ungroups frequency distribution table

Computation:

<u>Number of pets    Tally     Frequency</u>

0                              IIII             4

1                               IIIII I           6

2                              IIIII              5

3                              III               3

4                              II                 2

4 0
3 years ago
Write the equation of a line in slope-intercept form that passes through the point (0,-7) and has a slope of 3/4.
kondor19780726 [428]

Answer:

y=3/4x-7

Step-by-step explanation:

(0,-7) is the y-intercept

3/4 is the slope

y=mx+b

m is the slope

b is the y-intercept

plug it in:

y=3/4x-7

please mark brainliest!

4 0
2 years ago
Find the other two vertices of a square with one vertex (0, 0) and another vertex (4, 2). Can you find another answer?
Margarita [4]

It is given that two vertices of square are (0,0) and (4,2).

Now the problem is that you haven't given that whether these two vertices are adjacent vertices or opposite vertices of the square.

1. By Supposing that these two are adjacent vertices of Square

The third vertex will be at (-4,2) which lies in third quadrant.

Suppose the coordinate of fourth vertex be (x,y).

Mid point of line joining (4,2) and (-4,2) is{ [4+(-4)]/2,(2+2)/2} is (0,2).

Mid point of line joining (x,y) and (0,0) is (x/2,y/2).

Since diagonals of square bisect each other,

∵ x/2=0

⇒x=0

and

y/2=2

⇒y=4

So, The Coordinate of  fourth vertex is (0,4).

Now coming back to second condition if these are two opposite vertex of Square.

Let the third coordinate be (a,b).

Length of diagonal=\sqrt{(4-0)^2+(2-0)^2}=\sqrt20=2\sqrt5

Now,let side of Square be A.

Then length of Diagonal of square =√2 A

⇒√2 A=2√5

⇒A =√10

As third vertex is (a,b).

Using distance formula

a² + b²=10  -------------(1)

(a-4)²+ (b-2)²=10  --------------(2)

Solving expression (1) and (2), we get

⇒a²+ b²=(a-4)² +(b-2)²

⇒2a + b =5

⇒b=5-2a

Putting the value of b in (1),we get

⇒a² +(5-2a)²=10

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⇒5a²-20a+15=0

⇒a² - 4a + 3=0

Splitting the middle term,we get

⇒(a-3)(a-1)=0

⇒a=3  ∧  a=1

we get b=5-2×1=3 and b=5-2×3=5-6=-1

So,the other vertex are (1,3) and(3,-1).





3 0
3 years ago
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