Ask question

Ask question

All categories

2 years ago

11

Finsh the lyric: Time to go the distance

2 answers:

igomit [66]2 years ago

8 0

I believe I can fly, I believe I can’t touch the sky.

Advocard [28]2 years ago

4 0

Go the Distance

Song by Michael Bolton

I have often dreamed of a far off place

Where a hero's welcome would be waiting for me

Where the crowds would cheer, when they see my face

And a voice keeps saying this is where I'm meant to be

I'll be there someday, I can go the distance

I will find my way if I can be strong

I know every mile would be worth my while

When I go the distance, I'll be right where I belong

Down an unknown road to embrace my fate

Though that road may wander, it will lead me to you

And a thousand years would be worth the wait

It might take a lifetime but somehow I'll see it through

And I won't look back, I can go the distance

And I'll stay on track, no I won't accept defeat

It's an uphill slope

But I won't loose hope, 'till I go the distance

And my journey is complete, oh yeah…

You might be interested in

The ordered pairs on the graph represent a proportional relationship. What is the constant proportionality of Y to X

castortr0y [4]

A 7/4 because the slope of the line is 7/4

7 0

3 years ago

Help please .!!!!!!!!?

sammy [17]

15x over 2 dont know how to do it on computer

4 0

2 years ago

Read 2 more answers

F(x) = x^2 - 4, X is greater/less than 0<br><br> (a) Find the inverse function of f.<br> F^-1(x) =

Natali5045456 [20]

Step-by-step explanation:

f(x) = x² - 4

y = x²-4

x = y²-4

x + 4 = y²

$y = \sqrt{x + 4}$

7 0

2 years ago

A cylinder has a radius of 9 inches and a height of 5 inches. What is the volume and surface area of the cylinder?

Licemer1 [7]

The answer is:
v ≈ 1272.35 in^3

Sorry if this does not help.

4 0

3 years ago

Read 2 more answers

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0

3 years ago