Tina's aquarium has a capacity of 40 gallons or water. She plans to stock her aquarium with 0.25 inches of fish per quart of cap
1 answer:
Answer:
The number of mollies fishes in the aquarium is 20 .
Step-by-step explanation:
Given as :
The capacity of aquarium = 40 gallons
∵ 1 gallon = 4 quart
∴ 40 gallons = 4 × 40 = 160 quart
Now, According to question
0.25 inches of fish required 1 quart capacity
I.e for 1 quart capacity , 0.25 inches fish
So. for 160 quart capacity , 0.25 × 160 = 40 inches fishes
Now the size of mollies fish = 2 inches
Then , number of mollies fish =
I.e Number of mollies fish = = 20
Hence The number of mollies fishes in the aquarium is 20 . Answer
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1) small cone has r=5, and h=5
Volume small cone V1= 1/3 *π*5²*5 = 5³/3 *π
2) large cone has r=5, and h=21-6=15, h=15
Volume large cone V2= 1/3 *π*5²*15 = 5³*π
3) whole volume
5³/3 *π + 5³*π=5³π(1/3+1)=((5³*4)/3)π=(500/3)π≈166.7π≈523.6
Area
we see 2 right triangles,
Area of the triangle=1/2*b*h, where b -base, h -height
1) small one, b=5, h=5
A1=(1/2)*5*5=25/2
2)large one, b=5, h=15
A2=(1/2)*5*15=75/2
3) whole area=A1+A2=25/2+75/2=100/2=50
Volume of the cone V=1/3 *πr²*h
1) small cone has r=5, and h=5
Volume small cone V1= 1/3 *π*5²*5 = 5³/3 *π
2) large cone has r=5, and h=21-6=15, h=15
Volume large cone V2= 1/3 *π*5²*15 = 5³*π
3) whole volume
5³/3 *π + 5³*π=5³π(1/3+1)=((5³*4)/3)π=(500/3)π≈166.7π≈523.6
Area
we see 2 right triangles,
Area of the triangle=1/2*b*h, where b -base, h -height
1) small one, b=5, h=5
A1=(1/2)*5*5=25/2
2)large one, b=5, h=15
A2=(1/2)*5*15=75/2
3) whole area=A1+A2=25/2+75/2=100/2=50