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Dafna1 [17]
2 years ago
15

Plz help me out if you can​

Mathematics
1 answer:
Sindrei [870]2 years ago
3 0

Answer:

D $26

Step-by-step explanation:

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A customer left a 15% tip for a meal that cost $64. What was the total amount the customer paid for the meal and tip?
Inessa05 [86]

Answer:

73.6

Step-by-step explanation:

64x15%=9.6

9.6+64=73.6

4 0
2 years ago
How many times does the graph of 4x = 32 - x2 cross the x-axis?
garik1379 [7]

Answer:

The graph crosses the x-axis 2 times

The solutions are  x = -8  &  x = 4

Step-by-step explanation:

Qaudratics are in the form ax^2 + bx+ c

Where a, b, c are constants

Now, let's arrange this equation in this form:

4x=32-x^2\\x^2+4x-32=0

Where

a = 1

b = 4

c = -32

We need to know the discriminant to know nature of roots. The discriminant is:

D=b^2-4ac

If

  • D = 0 , we have 2 similar root and there is 2 solutions and that touches the x-axis
  • D > 0,  we have 2 distinct roots/solutions and both cut the x-axis
  • D < 0,  we have imaginary roots and it never cuts the x-axis

Let's find value of Discriminant:

D=b^2-4ac\\D=(4)^2 -4(1)(-32)\\D=144

Certainly D > 0, so there are 2 distinct roots and cuts the x-axis twice.

We get the roots/solutions by factoring:

x^2+4x-32=0\\(x+8)(x-4)=0\\x=4,-8

Thus,

The graph crosses the x-axis 2 times

The solutions are  x = -8  &  x = 4

6 0
3 years ago
Read 2 more answers
Given: △ACM, m∠C=90°, CP ⊥ AM
larisa86 [58]

Answer:  The answer is 3\dfrac{4}{7}.

Step-by-step explanation:  Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.

Now,

AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)

Comparing equations (A) and (B), we have

5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.

Thus,

AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.

8 0
4 years ago
How would I start to solve this? <br> Y=-1/3-1
statuscvo [17]

Answer:

<em>Y = -4/3</em>

Step-by-step explanation:

Subtract 1 from -1/3.

Y = -1/3 - 1

Y = -1/3 - 3/3

Y = -4/3

6 0
3 years ago
Factorize by splitting the middle term 6x-11x+4​
Gennadij [26K]

Answer: (2x - 1)(3x - 4)

(split -11x as -8x and -3x)

Step-by-step explanation:

I am assuming that it is actually 6x^2 - 11x + 4

To find out how to split the middle term: The two numbers should multiply to a*c (6*4 = 24) and add to b (-11)

-8, -3 works

(6x^2 - 8x) + (-3x + 4)

2x(3x - 4) + -1(3x - 4)

(2x - 1)(3x - 4)

5 0
3 years ago
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