Answer:
54$
Step-by-step explanation:
We know that for each 13$ Rob earns babysitting, he saves 9$. Thus, we can separate the money he earns into groups of 13, and for each group of 13, we can add 9$ to his savings.
Assume that Rob has 78$ lying on a table. He grabs 13 of them, leaving 65, and puts 9$ to the side for savings. He does this 5 more times (as 65 divided by 13 is 5, so Rob would make 5 groups of 13 out of his 65$ that is left), meaning that he now has 5+1 (the original group) = 6 groups of 9. 9*6=54, so he saves 54$. Please let me know if you have any further questions!
Answer:
x=-2 and y=-3
Step-by-step explanation:
2x+4y=-16
-2(-2x+2y=-2)
2x+4y=-16
4x-4y=4
6x=-12
x=-2
2x+4y=-16
2(-2)+4y=-16
-4+4y=-16
+4 +4
4y=-12
y=-3
Answer:
mad is 0
Step-by-step explanation:
what type of question is this? no offense
Answer: {(x + 2), (x - 1), (x - 3)}
Step-by-step explanation:
Presented symbolically, we have:
x^3 - 2x^2 - 5x + 6
Synthetic division is very useful for determining roots of polynomials. Once we have roots, we can easily write the corresponding factors.
Write out possible factors of 6: {±1, ±2, ±3, ±6}
Let's determine whether or not -2 is a root. Set up synthetic division as follows:
-2 / 1 -2 -5 6
-2 8 -6
-----------------------
1 -4 3 0
since the remainder is zero, we know for sure that -2 is a root and (x + 2) is a factor of the given polynomial. The coefficients of the product of the remaining two factors are {1, -4, 3}. This trinomial factors easily into {(x -1), (x - 3)}.
Thus, the three factors of the given polynomial are {(x + 2), (x - 1), (x - 3)}
Step-by-step explanation:
a triangular number n is the sum of all natural numbers <= n.
t1 = 1
t2 = 1+2 = 3
t3 = 1+2+3 = 6
t4 = 1+2+3+4 = 10
...
so,
tn = tn-1 + n
47.
1×8 + 1 = 9 is a square number.
3×8 + 1 = 25 is a square number
6×8 + 1 = 49 is a square number
10×8 + 1 = 81 is a square number
48.
1/3 = 0 remainder 1
3/3 = 1 remainder 0
6/3 = 2 remainder 0
10/3 = 3 remainder 1
15/3 = 5 remainder 0
21/3 = 7 remainder 0
28/3 = 9 remainder 1
so, there seems to be a pattern 1 0 0 1 0 0 1 0 0 1 ...
49.
1/4 = 0 remainder 1
4/4 = 1 remainder 0
9/4 = 2 remainder 1
16/4 = 4 remainder 0
25/4 = 6 remainder 1
36/4 = 9 remainder 0
49/4 = 12 remainder 1
so, there seems to be a pattern 1 0 1 0 1 0 1 0 1 0 1 ...
50.
polygonal numbers is the real name for this.
the formula for dimensions = 5 is
(3n² − n)/2
for dimensions = 6 it is
2n² - n
so, dimensions=5 (and therefore dividing also by 5) we get the remainders
1/5 = 0 remainder 1
5/5 = 1 remainder 0
12/5 = 2 remainder 2
22/5 = 4 remainder 2
35/5 = 7 remainder 0
51/5 = 10 remainder 1
70/5 = 14 remainder 0
92/5 = 18 remainder 2
117/5 = 23 remainder 2
145/5 = 29 remainder 0
here the pattern is 1 0 2 2 0 1 0 2 2 0 1 0 2 2 0 ...
dimensions=6 (and therefore dividing also by 6) we get the remainders
1/6 = 0 remainder 1
6/6 = 1 remainder 0
15/6 = 2 remainder 3
28/6 = 4 remainder 4
45/6 = 7 remainder 3
66/6 = 11 remainder 0
91/6 = 15 remainder 1
120/6 = 20 remainder 0
153/6 = 25 remainder 3
190/6 = 31 remainder 4
231/6 = 38 remainder 3
276/6 = 46 remainder 0
325/6 = 54 remainder 1
here the pattern is 1 0 3 4 3 0 1 0 3 4 3 0 1 0 3 4 3 0 ...
