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yawa3891 [41]
3 years ago
11

How many times does the graph of 4x = 32 - x2 cross the x-axis?

Mathematics
2 answers:
alina1380 [7]3 years ago
7 0

Answer:

1st:2

2nd:4,-8

Step-by-step explanation:

garik1379 [7]3 years ago
6 0

Answer:

The graph crosses the x-axis 2 times

The solutions are  x = -8  &  x = 4

Step-by-step explanation:

Qaudratics are in the form ax^2 + bx+ c

Where a, b, c are constants

Now, let's arrange this equation in this form:

4x=32-x^2\\x^2+4x-32=0

Where

a = 1

b = 4

c = -32

We need to know the discriminant to know nature of roots. The discriminant is:

D=b^2-4ac

If

  • D = 0 , we have 2 similar root and there is 2 solutions and that touches the x-axis
  • D > 0,  we have 2 distinct roots/solutions and both cut the x-axis
  • D < 0,  we have imaginary roots and it never cuts the x-axis

Let's find value of Discriminant:

D=b^2-4ac\\D=(4)^2 -4(1)(-32)\\D=144

Certainly D > 0, so there are 2 distinct roots and cuts the x-axis twice.

We get the roots/solutions by factoring:

x^2+4x-32=0\\(x+8)(x-4)=0\\x=4,-8

Thus,

The graph crosses the x-axis 2 times

The solutions are  x = -8  &  x = 4

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