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storchak [24]
3 years ago
14

15, 17, 22, 28, 32, 40, 16, 24, 25, 38 what is the value for qurtile 1?

Mathematics
1 answer:
Artist 52 [7]3 years ago
5 0

Answer:

17

Step-by-step explanation:

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Integers: 5[152-{7-8(9-2)}] please answer this​
Dmitry [639]

Answer:

1005

Step-by-step explanation:

1005

solve () {} []

ksjsksks

3 0
3 years ago
the present age of prisca and Ashmaal are in ratio 2:3 . After 4 yrs the ratio of their ages will be 4:5 the present age of pris
Solnce55 [7]

Answer:

he Present age of Prisca will be 4 years  .

Step-by-step explanation:

Given as :

The ratio of present age of Prisca and Ashmaal = 2 : 3

Let The present age of Prisca = 2 x  years

Let The present age of Ashmaal = 3 x  years

After 4 years , the ratio of present age = 4 : 5

i.e \frac{ 2 x + 4}{3 x + 4} = \frac{4}{5}

Or,  5 × (2 x + 4) = 4 × (3 x + 4)

Or, 10 x + 20 = 12 x + 16

Or, 12 x - 10 x = 20 - 16

Or, 2 x = 4

∴  x = \frac{4}{2}

i.e x = 2

So, The present age of Prisca = 2 x = 2 × 2 = 4 years

And The present age of Ashmaal = 3 x = 3 × 2 = 6 years

Hence, The Present age of Prisca will be 4 years  . Answer

4 0
4 years ago
In the chemistry lab an experiment requires 599 mL of one ingredient to be mixed with 1000 mL of another. How many ounces is the
raketka [301]

Answer:

50.7202

Step-by-step explanation:

(500ml+1000ml) / (29.574 ml per ounce) = 50.72 US Fluid Ounces

3 0
2 years ago
Is Joan read 74 pages in 4 hours how long will it take her to read 240 pages
kogti [31]

Answer:

It will take her 13 hours


5 0
3 years ago
Use the binomial expression (p+q)^n to calculate a binomial distribution with n=5 and p=0.3.(Show all steps)
Helen [10]

Answer:

The binomial in expanded form is (0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}.

Step-by-step explanation:

The Binomial Theorem states that a binomial of the form (a + b)^{n} can be expanded by using the following identity:

(a + b)^{n} = \Sigma \limits^{n}_{k = 0}\,\frac{n!}{k!\cdot (n-k)!}\cdot a^{n-k}\cdot b^{k} (1)

If we know that a = p = 0.3 and n = 5, then the expanded form of the binomial is:

(p+q)^{n} = \frac{243}{100000} + 5\cdot \left(\frac{81}{10000} \right)\cdot q + 10\cdot \left(\frac{27}{1000})\cdot q^{2} + 10\cdot \left(\frac{9}{100} \right)\cdot q^{3} + 5\cdot \left(\frac{3}{10} \right)\cdot q^{4} + q^{5}

(0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}

8 0
3 years ago
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