Answer:
Step-by-step explanation:
As C and D are both at y = -9, the line below V₂ is vertical and located at
x = ½(22 + (-2) = 10
The line between V₁ and V₂ will contain the point halfway between B and D.
x = ½(14 + (-2)) = 6
y = ½(7 + (-9)) = -1
(6, -1)
The slope of the line between V₁ and V₂ is the same as between V₁ and our just found midpoint between B and D
m = (5 - (-1)) / (0 - 6) = -1
so the line equation is
y = -x + 5
Which intersects x = 10 at
y = -10 + 5 = -5
V₂ = (10, -5)
The distance between V₂ and B, C, and D is
d = √((14 - 10)² + (7 - (-5))²) = √160
The distance between V₁ and B, A, and D is
d = √((-10 - 0)² + (15 - 5)²) = √200
As √200 > √160, the dump should be located at V₁ or at least √200 away from any two of the points
