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777dan777 [17]
4 years ago
14

4√3y-14√27y+6√12y Please show work.

Mathematics
1 answer:
Alex_Xolod [135]4 years ago
3 0
4\sqrt{3y} - 14\sqrt{27y} + 6\sqrt{12y} \\4\sqrt{3y} - 14\sqrt{9 * 3y} + 6\sqrt{4 * 3y} \\4\sqrt{3y} - 14\sqrt{9}\sqrt{3y} + 6\sqrt{4}\sqrt{3y} \\4\sqrt{3y} - 14(3)\sqrt{3y} + 6(2)\sqrt{3y} \\4\sqrt{3y} - 42\sqrt{3y} + 12\sqrt{3y} \\-38\sqrt{3y} + 12\sqrt{3y} \\-26\sqrt{3y}
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