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3 years ago

Is it more difficult to run up a ramp with a slope of 1/5 or a ramp with a slope of 5? Explain.

Mathematics

1 answer:

stich3 [128]3 years ago

6 0

Is it more difficult to run up a ramp with a slope of 1/5 or a ramp with a slope of 5? Explain.

a dlope of 1/5 is walkable; a slope of 5 is not without climbing gear.

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The ratio of tickets sold to see the incredible musical wicked to tickets sold to see Cats is 11 to 7 if there were 2700 total t

tia_tia [17]

Use algebra to set up 2 equations.

Assign c as number of tickets for CATS and w for number of tickets of WICKED

c + w = 2700

c / w = 7 / 11

Then solve for one of them in the first equation

c = 2700 - w

Then put this value for c into the 2nd equation

(2700 - w) / w = 7 / 11

Now cross multiply the numerator by denominator of both numerator and denominator pairs

7w = 11 x (2700 - w)
7w = 29700 - 11w

Now solve for w

7w = 26700 - 11w

Add +11w to both sides

18w = 29700

Now divide by 18 on both sides

w = 1650

Then c is the remainder of that ... 2700 - 1650 = 1050

You can also check because 7 / 11 = 1050 / 1650

8 0

3 years ago

Change 5x - y = 3 into slope-intercept form. © by – 5x+3

agasfer [191]

The slope intercept form is $y=5x-3$

Explanation:

The equation is $5 x-y=3$

Now, we shall bring the equation $5 x-y=3$ in the slope intercept form.

The general form of the slope intercept is given by

$y=mx+c$

Hence, we need to rewrite the given equation in this form.

Thus, we have,

$5 x-y=3$

Subtracting both sides of the equation by 5x, we get,

$-y=-5x+3$

Multiplying both sides of the equation by (-), we get,

$y=5x-3$

Thus, the slope intercept form of the given equation is $y=5x-3$

7 0

3 years ago

Adam started to run at a rate of 6 mph from city A towards city B, which is 18 miles away. Ten minutes later, Benjamin started t

amm1812

Answer:

Benjamin's rate in mph was 6.44

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Rate or speed of Adam = 6 mph
Ten minutes later, Benjamin started to run from city B towards city A
Simultaneously, Caroline started to bicycle at a rate of 11 mph from city A towards city B

2. If Caroline caught up to Benjamin 50 minutes after passing Adam, what was Benjamin's rate in mph?

A. Let's calculate when Caroline caught up Adam:

Adam's rate = 6 mph

Caroline's rate = 11 mph

10 minutes = 1/6 of an hour

Distance covered by Adam when Caroline started to bike = 6 * 1/6 = 1 mile

t = Time it took Caroline to catch up to Adam

Therefore, we can solve for t, this way:

11t = 6t + 1

11t - 6t = 1

5t = 1

t = 1/5 of an hour

t = 12 minutes

Caroline passed Adam after biking 12 minutes, therefore she caught up to Benjamin 50 minutes later, or after 62 minutes.

B. Let's calculate the distance she covered after 62 minutes, this way:

62 minutes = 1 hour and 2 minutes or 1 2/60 or 1.03

Distance covered by Caroline = Time * rate

Replacing with the values we have:

Distance covered by Caroline = 1 2/60 * 11

Distance covered by Caroline = 11 11/30 or 11.37 miles

Let's recall the distance from city A to city B is 18 miles, therefore Benjamin covered 6.63 miles (18 - 11.37) when Caroline caught up to him

C. Finally let's calculate Benjamin's rate, this way:

Rate = Distance/Time

Replacing with the values we know:

Rate = 6.63/1.03

Rate = 6.44 mph (rounding to the next hundredth)

5 0

3 years ago

B. Un autobús hace diariamente tres viajes de ida y

Lerok [7]

Answer:

BEANSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS

Step-by-step explanation:

6 0

2 years ago

Two buses leave Houston at the same time and travel in opposite directions. One bus averages 55 mi/hr and the other bus averages

maks197457 [2]

If they are traveling in different directions then you add up the two mi/hr then whatever you have to multiply the sum by is the number of hours. By the way the sender is 4 hours.

3 0

4 years ago