We have been given that Judy’s brother Sam has a collection of 96 comic books.
We have been asked to find the 10 ways Sam could divide his comic books into equal groups.
This can be done as follows:
96 can be written as .
Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.
Likewise, 96 can also be written as . Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.
Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a total of 10 ways in which Sam can divide his comic books into equal groups.
Don’t take my word for it but I think 3rd option
Answer:
(B) x=\sqrt{30}
Step-by-step explanation:
It’s C! that’s the answer, hope it helps
Answer:
Step-by-step explanation:
Let's do the obvious things first.
Right rectangle
w = 11
L = 17
Formula
Area = L * W
Area = 11 * 17
Area = 187
Left rectangle
W = 8
L = 11
Area = 8 * 11= 88
Middle Rectangle
W = 11
L = 15
Area = 11 * 15 165
Now we come to the triangles. It's not obvious what to do with them. You have to infer that one of the lets is 8 and the other is 15. You get the 8 from the width of the left rectangle (see above.)
There are 2 triangles
Area = 2 * 1/2 * l1 * l2
Leg 1 = 8
Leg2 = 15
Area = 2 * 1/2 (8 * 15)
Area = <u> 120 </u>
Total = 120 + 165 + 88 + 187 = 560
Unless you have an E answer that is 560, my answer does not agree with any of the given answers. I would suggest that you ask your teacher how it is done. My method is correct.
