Which pair of expressions is equivalent?

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

3 0

Answer:

Step-by-step explanation:

7(1–k)

= 1(7) -k(7) -------------> distributive property

= 7–7k

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The x-intercepts of the gravy of f (x)= x (x+1)(x-5)(x-7) are

Serhud [2]

"Of the gravy" lol

To find the x-intercepts, you make f(x) = 0 and solve for x by setting each factor equal to 0.

0 = x(x + 1)(x - 5)(x - 7)

x = 0

x + 1 = 0
x = - 1

x - 5 = 0
x = 5

x - 7 = 0
x = 7

Your x-intercepts are x = - 1, 0, 5, 7

OR

There are x-intercepts at (- 1, 0), (0, 0), (5, 0), and (7, 0).

8 0

3 years ago

In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively.

Irina-Kira [14]

Given the values of the three sides of the triangle, we can apply the Cosine Law to find the angles of the triangle. Recall that for we can express the value of c through the equation below.

$c^{2} = a^{2} + b^{2} - 2abcosC$

Rearranging this equation, we can find the value ∠C as shown below.

$\cos C = \frac{a^{2}+b^{2}-c^{2}}{2ab}$
$C = cos^{-1} (\frac{a^{2}+b^{2}-c^{2}}{2ab})$

We can apply the same reasoning for finding the value of ∠B as shown.

$B = cos^{-1} (\frac{a^{2}+c^{2}-b^{2}}{2ac})$

Plugging in the values of the sides (see image attached) from the given. It will now be straightforward to compute for ∠B and ∠C.

$C = cos^{-1} (\frac{22.5^{2}+18^{2}-13.6^{2}}{2(22.5)(18)})$
$C \approx 37.19$

$B = cos^{-1} (\frac{22.5^{2}+13.6^{2}-18^{2}}{2(22.5)(13.6)})$
$B \approx 53.13$

Answer: ∠C = 37.19° and ∠B = 53.13°