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3 years ago

What is the sum of -1/2 and 8/6? Please help! I need to pass this test! 15 points!

Mathematics

1 answer:

notsponge [240]3 years ago

3 0

Answer: C) 5/6

Step-by-step explanation:

-1/2= -3/6 + 8/6 is 5/6

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Gareth 30 students in a class and the ratio of boys to girls in the class is 2:3 calculate the number of goals

pishuonlain [190]

Answer:

<em>There are 12 boys and 18 girls</em>

Step-by-step explanation:

<u>Equations</u>

There are 30 students in a class. Let's call:

x = number of boys

Since the sum of boys and girls is 30:

30 - x = number of girls

The ratio of boys to girls is 2:3, thus:

$\displaystyle \frac{x}{30-x}=\frac{2}{3}$

Crossing denominators:

3x = 2(30 - x)

Operating the parentheses:

3x = 60 - 2x

Adding 2x:

5x = 60

Dividing by 5:

x = 60/5 = 12

x = 12

There are 12 boys and 30-12=18 girls

8 0

3 years ago

You are directed to give a heroin addict 30 mg of methadone PO. the medication comes in tablets labeled 20 mg/tablet.How many ta

Ber [7]

I'm assuming 1.5 tablets

6 0

3 years ago

Find the possible values for m<1

Anuta_ua [19.1K]

0.5 that would be half of one if one is greater than the variable M

I really hope this helped ... have a great day !

4 0

3 years ago

John worked 43 hours last week. His hourly rate is $9.00. He has the following deductions taken from his pay: Social Security ta

disa [49]

Assuming John does not get premium pay for hours over 40, his pay will be ...

... 43 hours × $9.00 = $387

... - 6.2% × $387 = $23.99

... - 1.45% × $387 = $5.61

... - $15.00

... - 5% × $387 = $19.35

... - 10% × ($387 -19.35) = $36.77

... = $286.28 . . . . net pay after all the deductions

6 0

3 years ago

Read 2 more answers

1. In an auditorium, there are 21 seats in the first row and 26 seats in the second row. The number of seats in a row continues

kondor19780726 [428]

1. Let $s_n$ be the number of seats in the $n$ -th row. The number seats in the $n$ -th row relative to the number of seats in the $(n-1)$ -th row is given by the recursive rule

$s_n=s_{n-1}+5$

Since $s_1=21$ , we have

$s_2=s_1+5$
$s_3=s_2+5=s_1+2\cdot5$
$s_4=s_3+5=s_1+3\cdot5$
$\cdots$
$s_n=s_{n-1}+5=\cdots=s_1+(n-1)\cdot5$

So the explicit rule for the sequence $s_n$ is

$s_n=21+5(n-1)\implies s_n=5n+16$

In the 15th row, the number of seats is

$s_{15}=5(15)+16=91$

2. Let $p_n$ be the amount of profit in the $n$ -th year. If the profits increase by 6% each year, we would have

$p_2=p_1+0.06p_1=1.06p_1$
$p_3=1.06p_2=1.06^2p_1$
$p_4=1.06p_3=1.06^3p_1$
$\cdots$
$p_n=1.06p_{n-1}=\cdots=1.06^{n-1}p_1$

with $p_1=40,000$ .

The second part of the question is somewhat vague - are we supposed to find the profits in the 20th year alone? the total profits in the first 20 years? I'll assume the first case, in which we would have a profit of

$p_{20}=1.06^{19}\cdot40,000\approx121,024$

3. Now let $p_n$ denote the number of pushups done in the $n$ -th week. Since $3\cdot4=12$ , $12\cdot4=48$ , and $48\cdot4=192$ , it looks like we can expect the number of pushups to quadruple per week. So,

$p_n=4p_{n-1}$

starting with $p_1=3$ .

We can apply the same reason as in (2) to find the explicit rule for the sequence, which you'd find to be

$p_n=4^{n-1}p_1\implies p_n=4^{n-1}\cdot3$

6 0

3 years ago