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taurus [48]
3 years ago
6

Which solution set is graphed on the number line? O x21 O x>1 0x<1 O x51

Mathematics
1 answer:
Mkey [24]3 years ago
3 0

Answer:

x < 1

Step-by-step explanation:

x is less than 1, we can see

we have an open circle, so <u>x is </u><u>only less</u><u> than 1</u>

it does not include 1

so answer is x < 1

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Please help me! i would appreciate it
vagabundo [1.1K]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
What is the slope of line which goes through the points (-2,-1) and (2,3)?
Nat2105 [25]

Answer:

1

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(3-(-1))/(2-(-2))

m=(3+1)/(2+2)

m=4/4

m=1

6 0
3 years ago
Read 2 more answers
First you to find the worksheet and download it<br> plase I need help
Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = 3^{x + 2}

The asymptote is given as x → -∞, f(x) = 3^{x + 2} → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = 3^{0 + 2} = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = 5^{1  - x}

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = 5^{1  - 0} = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = 2^{x + 3} - 1

The asymptote is 2^{x + 3}  → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) =  2^{0 + 3} - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, 2^{x + 3} - 1 = 0

2^{x + 3} = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2

The asymptote is \left (\dfrac{1}{2} \right)^{x - 2} → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6

The y-intercept is (0, 6)

7 0
2 years ago
Anyone Know This Answer ASAP ?
Luda [366]

multiply 35 by tan(42)

 this equals 31.5141

rounded to 31.51

4 0
3 years ago
Simplify the expression <br> 4(-8x+5)-(-33x-26)=
Pavel [41]

Answer:

x+46

Explanation:

4(−8x+5)−(−33x−26)

Distribute the Negative Sign:

=4(−8x+5)+−1(−33x−26)

=4(−8x+5)+−1(−33x)+(−1)(−26)

=4(−8x+5)+33x+26

Distribute:

=(4)(−8x)+(4)(5)+33x+26

=−32x+20+33x+26

Combine Like Terms:

=−32x+20+33x+26

=(−32x+33x)+(20+26)

=x+46

3 0
3 years ago
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