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natali 33 [55]
3 years ago
11

Why was a book in the frying pan on the stove (5.3) puzzle time grade 6

Mathematics
1 answer:
lesya [120]3 years ago
3 0
What do you need what are choice do you need this in a paragraph
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A student has 10 coins in her pocket that have a value of $0.85. The coins are either
il63 [147K]

Answer:

\left\{\begin{matrix}x+y=10\\ 0.05x+0.10y=0.85\end{matrix}\right.

Step-by-step explanation:

<u>System of Equations</u>

Let's call:

x = number of nickels in the student's pocket

y = number of dimes in the student's pocket

Each nickel has a value of $0.05, so x nickels have a value of 0.05x

Each dime has a value of $0.10, so y dimes have a value of 0.10y

The student has a total of 10 coins, thus:

x+y=10

The total value of the coins is $0.85, thus

0.05x+0.10y=0.85

The system of linear equations that represents this scenario is:

\left\{\begin{matrix}x+y=10\\ 0.05x+0.10y=0.85\end{matrix}\right.

5 0
3 years ago
What is the 4 math methods
erastovalidia [21]
The Four basic Mathematical Operations are:
•Addition
•Subtraction
•Multiplication
•Division
5 0
3 years ago
A service attendant is paid time and a 1/2 for working over 40 hours per week last week. The attendant work 47 hours and earned
devlian [24]
Write and solve an equation:

Total earnings = $782.75 = s(40 hrs) + 1.5*s*(7 hrs)

Then 782.75 = 40s + 10.5s = 50.5s

Dividing both sides by 50.5:  s = 15.5.  The attendant's regular hourly wage was $15.50.
5 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
A circle is defined by the equation x2 + y2 – x – 2y – = 0. What are the coordinates for the center of the circle and the length
madreJ [45]
X^2 + y^2 - x - 2*y = 0
To find both coordinates and radius we need to make this equation in circle form:
(x-a)^2 + (y-b)^2 = r^2

x^2 - 2*1/2*x + 1/4 - 1/4 + y^2 - 2*1*y + 1 - 1 = 0
Here we are adding and subtracting numbers in order to get square binomial.
(x - 1/2)^2 + (y-1)^2 = 5/4

coordinates of center are (1/2,1) and the radius is √\frac{5}{4}
6 0
3 years ago
Read 2 more answers
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