Answer:
30
Step-by-step explanation:
The ring operator signifies a composition of functions. The composition is evaluated right-to-left. That means the composition ...

should be interpreted to mean ...

___
To evaluate f(g(6)), we first evaluate g(6):
g(6) = 6² -5 = 31
Then we evaluate the function f using that as its argument:
f(31) = 31 -1 = 30
f(g(x)) = 30
Answer:
Side of 22 and height of 11
Step-by-step explanation:
Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:


As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank
Base area with open top 
Side area 4sh
Total surface area 
We can substitute 


To find the minimum of this function, we can take the first derivative, and set it to 0



![s = \sqrt[3]{10648} = 22](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%5B3%5D%7B10648%7D%20%3D%2022)

The IUPAC name for a binary covalent compound lack prefixes such as mono, di, tri tetra etc.
A binary compound is a compound that is composed of only two elements. Many binary compounds could be made up of a metal and a nonmetal or even two nonmetals as the case may be. Examples of binary compounds include; SO2, NaH, K2S etc.
We must note that a binary covalent compound uses Roman numerals to indicate the oxidation state of the central atom in the compound. For instance, SO2 is called Sulfur IV oxide.
Hence, the IUPAC name for a binary covalent compound lack prefixes such as mono, di, tri tetra etc.
Lear more about IUPAC: brainly.com/question/11587934
Given:
<span>11 11.5 10.5 17 14.5 14.5 18 17 19
Arrange in chronological order from least to greatest.
10.5 ; 11 ; 11.5 ; 14.5 ; 14.5 ; 17 ; 17 ; 18 ; 19
</span><span>I used an online lower and upper fence calculator to get the necessary data.
Minimum: 10.5
Maximum: 19
Q1: 11.25
Q2 or median: 14.5
Q3: 17.5
Interquartile range can be solved by subtracting the value of Q1 from the value of Q3
IQR = Q3 - Q1
IQR = 17.5 - 11.25
IQR = 6.25 CHOICE A. </span>