F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
13 songs per cd 4/4 and 52/4= 1/13
The formula for the average value of a function is
where b is the upper bound and a is the lower. For us, this formula will be filled in accordingly.
. We will integrate that now:
![\frac{1}{2}[ \frac{2x^3}{3}+3x]](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%5B%20%5Cfrac%7B2x%5E3%7D%7B3%7D%2B3x%5D%20%20)
from 0 to 2. Filling in our upper and lower bounds we have
![\frac{1}{2}[( \frac{2(2^3)}{3}+3(2))-0]](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%5B%28%20%5Cfrac%7B2%282%5E3%29%7D%7B3%7D%2B3%282%29%29-0%5D%20%20)
which simplifies to
and
which is 17/3 or 5.667
First you have to solve both inequalities,
3x-1>8
3x>9
x>3
and the other one
2x≤4
x≤2
then you graph each one on the number line
the graph says or, so the solution can satisfy either equation
the solution would be all real numbers except three
the way to write it is x≠3
Answer:
f ( - 2 ) = - 12
Step-by-step explanation:
f ( - 2 ) = - 3 ( -2 )^2
then you do the exponent first so
- 3 ( 4 )
now you multpily the - 3 and 4
you get - 12
