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marissa [1.9K]
3 years ago
10

The quotient of 6 divided by the difference of m minus 3A.15B.2C.3D.21E.42​

Mathematics
1 answer:
anzhelika [568]3 years ago
6 0
A i hope this helps!!
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First to answer gets brainliest!
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it is the first one

Step-by-step explanation:

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Suppose a box contains 3 defective light bulbs and 12 good bulbs. two bulbs are chosen from the box without replacement. find th
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The probability that the bulb is good is 12/15.
Since we have taken 1 item out the remaining total is now 14, so the probability of getting a defective bulb is now 3/14.
Now you multiply the probabilities together to get (12/15)(3/14)=(4/5)(3/14)=12/70=6/35
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Benjamin buys a candy apple that was on sale for 20% off he paid with a five dollar bill and received 1.80 dollars in change wha
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3 years ago
Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr
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Answer:

  \log{\dfrac{3\sqrt{x}(x^3+4)}{2}}

Step-by-step explanation:

\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}

__

The applicable rules of logarithms are ...

  log(ab) = log(a) +log(b)

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  log(a^b) = b·log(a)

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3 years ago
ABCD is a parallelogram. AB>AD. Prove: m∠ADB>m∠BDC. Show your work (statement reason maybe?)
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In the parallelogram ABCD, join BD.

Consider the triangle Δ ABD.

It is given that AB > AD.

Since, in a triangle, angle opposite to longer side is larger, we have,

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Also, AB || DC and BD is a transversal.

Therefore,

∠ ABD = ∠ BDC

Substitute in (1), we get,

∠ ADB > ∠ BDC.

7 0
3 years ago
Read 2 more answers
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