Answer:
<em>The magnitude of the velocity will be 60 m/s.</em>
<em>The distance covered is 3,600 m</em>
Step-by-step explanation:
<u>Constant Acceleration Motion</u>
It's known as a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
If a is the constant acceleration, vo is the initial speed, vf the final speed, and t the time, the following relation applies:
The distance traveled by the object is calculated as:
The bus starts from rest, i.e. vo=0, the acceleration is a=0.5 m/s^2. The magnitude of the velocity at t=2 minutes = 120 seconds is:
The magnitude of the velocity will be 60 m/s.
The distance covered during that time is:
x = 3,600 m
The distance covered is 3,600 m
Answer:
it is A swear to god
Step-by-step explanation:
Answer:
(1) False
(2) False
(3). False
(4) False
Step-by-step explanation:
According to the problem, calculation of the given data are as follows,
(1). Given, 149 + 769 = 819
By calculating 149 + 769 = 918
Hence, False
(2). Given, 556 + 336 = 826
By calculating 556 + 336 = 892
Hence, False
(3). Given, 458 - 248 = 238
By calculating 458 - 248 = 210
Hence, False
(4). Given, 658 - 228 = 438
By calculating 658 - 228 = 430
Hence, False
<h3>
Question: </h3><h3>
In the diagram below of Δ ABC, side BC is extended to point D, m∠A = x , m∠B = 2x+15, and m∠ACD = 5x+5 , what is m∠B ?</h3>
Answer: 3) m∠B = 25º
Step-by-step explanation:
Since m∠C is supplementary to m∠ACD
m∠C = 180º - m∠ACD
m∠C = 180º -(5·x + 5)
m∠C = 180º -5 -5·x
m∠C = 175º - 5·x
The sum of the angles of a triangle = 180º
m∠A + m∠B + m∠C = 180º
x + 2·x + 15º + 175º - 5·x = 180º
3·x - 5·x +190º = 180º
-2·x = 180º - 190º
-2·x = -10º
x = -10º/-2 = 5º
Now we can substitute this value of x in m∠B
m∠B = 2x+15
m∠B = 2·x + 15º = 2·5º + 15º = 10º + 15º = 25º
Answer: 3) m∠B = 25º
<h2><em>Spymore</em></h2>