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schepotkina [342]
3 years ago
6

How mucho Does it cost to buy 12 meals if each 3 Meals cost $7.25$ explain please

Mathematics
2 answers:
choli [55]3 years ago
4 0

\bf \begin{array}{ccll}meals&\$\\\cline{1-2}3&7.25\\12&x\end{array}\implies \cfrac{3}{12}=\cfrac{7.25}{x}\implies \cfrac{1}{4}=\cfrac{7.25}{x}\\\\\\ x=\cfrac{4\cdot 7.25}{1}\implies x=29

andrew-mc [135]3 years ago
3 0

So if you have 12 meals and each 3 cost $7.25 then the cost to buy them all is $29.

We can figure this out by dividing each of the meals into groups of 3, and we would get four total groups of 3.

Then we multiply 7.25 by 4 and we get 29, which is the final answer.

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Answer answer please please
denpristay [2]

Answer: The answer is the first choice ( >)

Step-by-step explanation: 4.3 × 10⁶ = 4300000 . 12.1 × 10⁵ = 1210000 . So 4300000 is greater than 1210000 . HOPE IT HELPS YOU . PLEASE GIVE BRAINLIEST . THANKS .

7 0
2 years ago
your patient has a 2500 cc bag of irrigation solution hanging, and 750 cc of fluid has been infused. what percentage of irrigati
nlexa [21]

Answer:  30%

Step-by-step explanation:

Given : Patient has a 2500 cc bag of irrigation solution hanging.

Irrigation has been infused = 750cc

Then, the percentage of irrigation solution has been infused :

\dfrac{\text{ fluid infused}}{\text{Total irrigation solution}}\times100\\\\=\dfrac{750}{2500}\times100\\\\= 30\%

Hence, the percentage of irrigation solution has been infused = 30%

6 0
3 years ago
Find the product of all real values of r for which 1/2x=r-x/7
Dahasolnce [82]

Answer:

r = \±\sqrt{14

Product = -14

Step-by-step explanation:

Given

\frac{1}{2x} = \frac{r - x}{7}

Required

Find all product of real values that satisfy the equation

\frac{1}{2x} = \frac{r - x}{7}

Cross multiply:

2x(r - x) = 7 * 1

2xr - 2x^2 = 7

Subtract 7 from both sides

2xr - 2x^2 -7= 7 -7

2xr - 2x^2 -7= 0

Reorder

- 2x^2+ 2xr  -7= 0

Multiply through by -1

2x^2 - 2xr +7= 0

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

b^2 - 4ac = 0

For a quadratic equation

ax^2 + bx + c = 0

By comparison with 2x^2 - 2xr +7= 0

a = 2

b = -2r

c =7

Substitute these values in b^2 - 4ac = 0

(-2r)^2 - 4 * 2 * 7 = 0

4r^2 - 56 = 0

Add 56 to both sides

4r^2 - 56 + 56= 0 + 56

4r^2 = 56

Divide through by 4

r^2 = 14

Take square roots

\sqrt{r^2} = \±\sqrt{14

r = \±\sqrt{14

Hence, the possible values of r are:

\sqrt{14 or -\sqrt{14

and the product is:

Product = \sqrt{14} * -\sqrt{14}

Product = -14

8 0
3 years ago
  14.51 less than the product of 26 and x
Mekhanik [1.2K]

<em>the</em><em> </em><em>pro</em><em>duct</em><em> </em><em>of</em><em> </em><em>2</em><em>6</em><em> </em><em>and</em><em> </em><em>x</em><em> </em><em>is</em><em> </em><em>wri</em><em>tten</em><em> </em><em>as</em>

<em>2</em><em>6</em><em> </em><em>times</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em>6</em><em>x</em>

<em>= 14.51 < 26x</em>

<em>= 1451 \times  {10}^{ - 2}  < 26x</em>

6 0
3 years ago
Lena and Jade had a total of $36. Lena had twice as much as Jade. After each of them bought a movie ticket. Lena had 3 times as
marusya05 [52]
Lena had $24 at the beginning
the movie ticket was $6
it's just basic algebra
4 0
3 years ago
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