Girl it’s D, i’m kidding i don’t know but what grade are you in this looks easy
Answer:
A = 1100cm^2
Step by step Explanation:
given the dimensions of width and length of the picture are x+20 by 2x-10 and the frame is a constant 5 cm wider from the edge of the picture to the frame, than the area of the frame is defined as (x+30)(2x)-(x+20)(2x-10) = 30x+200.
If the width is equal to the length which I assume is true if the width is constant.
than x+30=2x, which means x = 30.
if this is true than 30(30)+200 = 1100cm^2
5x+ (5)15
or
5(x+15)
I hope this helps
Answer:
- 34 < x < 10
Step-by-step explanation:
Inequalities of the type | x | < a, always have a solution of the form
- a < x < a
given | x + 12 | + 5 < 27 ( subtract 5 from both sides )
| x + 12 | < 22, then
- 22 < x + 12 < 22 ( subtract 12 from all 3 intervals )
- 34 < x < 10
Answer:
22.05
Step-by-step explanation: