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iren [92.7K]
3 years ago
12

Which statements about the relationship between the two triangles below are true? Check all that apply. Triangle A C D. Angle D

is 60 degrees and angle A is 74.9 degrees. Triangle R S T. Angle R is 74.9 degrees and angle S is 45.1 degrees.
Mathematics
1 answer:
Bezzdna [24]3 years ago
5 0

Answer:

Triangles are similar using AAA rule of similarity.

Step-by-step explanation:

Let's take triangle ACD. Where <D =60 degrees. <A =74.9 degrees and let's find <C using angle sum property of a triangle.

Please remember the sum of interior angle of a triangle is 180 degrees.

So, m<D= 180-60-74.9 =45.1 degrees.

Other triangle RST has the two angles as 74.9 degrees and 45.1 degrees.

So, third angle <T= 180-74.9-45.1= 60 degrees.

If we see the angles of a triangle, both has same angle measures.

That's <A= <R

<C= <S

<D= <T

So, the triangles are similar using AAA rule of similarity.

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[HELP PLEASE ALGEBRA] <br><br> Would the answer only be B?
Salsk061 [2.6K]
Hello,

|x+4|=3x-5
if x+4>=0 then
          |x+4|=x+4
          x+4=3x-5
          2x=9
            x=9/2
else
    x+4<0 : x<-4
    |x+4|=-(x+4)
     -(x+4)=3x-5
    -x-4=3x-5
    4x=1
    x=1/4 : to exclude since x<-4
end if


Only one solution : x=9/2
ANSWER B.
7 0
3 years ago
Complete the steps to factor 2x2+6x+5x+15 by grouping
Nataly_w [17]

Answer:

4+11x+15

Step-by-step explanation:

2×2=4 and 6x+5x=11× therefore 15 is left alone

4 0
3 years ago
I NEED HELP ASAP PLEASE HELP ME
Tju [1.3M]

Answer:

The avergae temp rose 51° F.

Step-by-step explanation:

Average temp in January = -8°F

Average temp in March = 43°F

-8 is 8 away from 0 (absolute value)

43 is 43 away from 0 (absolute value)

43 + 8 = 51

The average temp rose 51°F

5 0
4 years ago
A rectangle is 5.1 cm wide and each diagonal is 9.3 cm long. What is the measure of the angle between a diagonal and the shorter
Anastasy [175]

Answer:

56.7°

Step-by-step explanation:

A rectangle is 5.1 cm wide and each diagonal is 9.3 cm long. What is the measure of the angle between a diagonal and the shorter side of the rectangle to the nearest tenth of a degree?

We solve this question using the Trigonometric function of Sine

From the question, we are told that:

A rectangle is 5.1 cm wide

and each diagonal is 9.3 cm long.

Since we have a diagonal, this means the shape is transformed to a triangle.

The width of the rectangle = Adjacent side of a triangle = 5.1cm

The diagonal of the rectangle = Hypotenuse = 9.3cm

Hence,

cosθ = Adjacent/Hypotenuse

cosθ = 5.1/9.3

cosθ = 0.5483870968

θ = arccos(0.5483870968)

θ = 56.743568714°

Approximately = 56.7°

The measure of the angle is 56.7°

3 0
3 years ago
Someone please help!!
Andrej [43]

Answer:

Vertex is (-1/4, -81/8)

Step-by-step explanation:

Does that help any?

7 0
2 years ago
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