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iren [92.7K]
2 years ago
12

Which statements about the relationship between the two triangles below are true? Check all that apply. Triangle A C D. Angle D

is 60 degrees and angle A is 74.9 degrees. Triangle R S T. Angle R is 74.9 degrees and angle S is 45.1 degrees.
Mathematics
1 answer:
Bezzdna [24]2 years ago
5 0

Answer:

Triangles are similar using AAA rule of similarity.

Step-by-step explanation:

Let's take triangle ACD. Where <D =60 degrees. <A =74.9 degrees and let's find <C using angle sum property of a triangle.

Please remember the sum of interior angle of a triangle is 180 degrees.

So, m<D= 180-60-74.9 =45.1 degrees.

Other triangle RST has the two angles as 74.9 degrees and 45.1 degrees.

So, third angle <T= 180-74.9-45.1= 60 degrees.

If we see the angles of a triangle, both has same angle measures.

That's <A= <R

<C= <S

<D= <T

So, the triangles are similar using AAA rule of similarity.

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Determine the range of the following graph:
Alex Ar [27]

Answer:

-9≤y≤0

Step-by-step explanation:

-4≤x≤4 DOMAIN

-9≤y≤0 RANGE

I'm pretty sure this is correct but I haven't done it in a while

8 0
2 years ago
Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}

r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

(x-(-2))^2+(y-0)^2=\sqrt{5} ^2

on simplification is

x^{2} +y^{2}+4 x-1=0

5 0
2 years ago
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Now w can take 2* AM
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3 years ago
Please answer correctly 50 points
tankabanditka [31]

Answer: It would be the number 1 since they all cancel each other out

Step-by-step explanation:

8 0
1 year ago
Read 2 more answers
Somebody could help me ? ..
Hoochie [10]

Answer:

1/5

Step-by-step explanation:

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