Answer:
The average cost of each dinner at Dave's party is <u>$5.79</u>.
Step-by-step explanation:
Given:
Dave ordered dinner for a party of 10 people.
Three people ordered the $4.75 chicken dinner, two people ordered the $4.95 fish dinner, and five had the beef dinner at a cost of $6.75 each.
Now, to find the average cost of each dinner at Dave's party.
So, we get the total amount for the dinner:
Three people ordered the $4.75 chicken dinner.

Two people ordered the $4.95 fish dinner.

Five had the beef dinner at a cost of $6.75.

Total amount of dinner = 
Now, to get the average cost of each dinner of 10 people we divide the total amount of dinner by 10:


Therefore, the average cost of each dinner at Dave's party is $5.79.
Answer:
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2 YES CHILEEEEEEE Chile chicle Chile choemmdkemsndnsjjsjsksksksks
we are given
system of equations
First equation is

Second equation is

now, we can find augmented matrix

now, we can change it into reduced row echelon form
step-1: multiply the 1st row by 1/3

step-2:add -3 times the 1st row to the 2nd row

step-3:multiply the 2nd row by 1/4

step-4: add 2/3 times the 2nd row to the 1st row

so, we get

Answer is (5,-8)