b. It depends on the value you assume for the power line voltage. If you assume it is 120 volts, then the ratio to battery voltage is
... (120 volts)/(1.2 volts) = 100
Power line voltage is 100 times as large as battery voltage.
_____
Please be aware of some difficulties in this question.
1. Power line voltage, even if it is "120 volts" varies over time from -170 V to +170 V, so is not really comparable to a battery's voltage, which is steady at 1.2 V.
2. The terminology "times larger" is ambiguous. When we answer the question, "how much larger is <em>a</em> than <em>b</em>," we give the response in terms of the difference a-b. Thus, if <em>a</em> is 2 times <em>larger</em> than <em>b</em>, we might be talking about the <em>difference</em> being twice the value of <em>b</em>. It is preferable to say "times as large as."
Answer:
Step-by-step explanation:
Solution
This (after combining the top 2 fractions, is a 4 tier fraction.
1/4*3/4 = 3/16
So the question now becomes 3/16 ÷ 10/3
The rule for such a question is invert (turn up side down) the second fraction and multiply.
3/16 * 3/10 Combine
(3*3)/(16* 10)
9 / 160
0.05625
<u>ANSWER: </u>
Jack picked 10 ears of corn. The amount of corn left is 
ears of initial corn.
<u>SOLUTION:
</u>
Given, Jack picked 10 ears of corn.
Now the total corn present is 10 ears.
He and two of his sisters ate two each.
Then, remaining corn = 10 ears – eaten corn
= 10 – 2 (by him) – 2 (by his first sister) -2 (by his second sister)
= 10 – 6 = 4
Now, the amount of corn left in fraction is remaining corn divided by initial corn.
Left over corn = 
Hence, the amount of corn left is ears of initial corn.
Answer: 334
Step-by-step explanation:
6 consecutive numbers can be written as:
n, n+1, n+2, n + 3, n + 4, n + 5,
The addition of those 6 numbers is:
n + n+1 + n+2 + n + 3 + n + 4 + n + 5
6n + 1 + 2 + 3 + 4 + 5 = 6n + 15
Let's find the maximum n possible:
6n + 15 = 2020
6n = 2020 - 15 = 2005
n = 2005/6 = 334.16
The fact that n is a rational number means that 2020 is can not be constructed by adding six consecutive numbers, but we know that with n = 334 we can find a number that is smaller than 2020, and with n = 335 we can found a number bigger than 2020.
So with n = 334 we can find one smaller.
6*334 + 15 = 2019
and we can do this for all the values of n between 1 and 334, this means that we have 334 numbers less than 2020 that can be written as a sum of six consecutive positive numbers.
