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lakkis [162]
3 years ago
10

A taxi charges $20 flat fee for the first 5 miles (even if it takes the rider one mile the cost is $20) and after that the addit

ional miles cost $1.20 per mile. A trip that covers 7 miles will cost $22.40. Write a piecewise function for the cost of a cab ride assuming the miles will be whole numbers.
Mathematics
1 answer:
Free_Kalibri [48]3 years ago
7 0
Ok so, we have the fact that 1.20 per mile Lets represent m as each additional mile so we have 1.20m which is That much per additional mile So For the first 5 functions we have f(1) = 20 f(2) = 20 f(3) = 20 f(4) = 20 f(5) = 20 Only for the first 5 miles though, since it is a flat fee. So for the additional miles we go back to what I said in the first Paragraph. 1.20m That is for additional miles, so that will be added to 20 So if you travel more than 5 miles the function looks like this: f(x) = 20 + 1.20m So the first 5 miles it is: f(x) = 20 For 7 mles the function would look like: f(7) = 20 + 1.20(2) It is a 2 because it is the additional mile, which is 2  hope this helps
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B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =
jolli1 [7]

I suppose you mean

g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)

Differentiate one term at a time.

Rewrite the first term as

\dfrac x{2\sqrt{36-x^2}} = \dfrac12 x(36-x^2)^{-1/2}

Then the product rule says

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'

Then with the power and chain rules,

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}

Simplify this a bit by factoring out \frac12 (36-x^2)^{-3/2} :

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}

For the second term, recall that

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