Hey!
Dean's family has been traveling on the same speed for two days, so to find how far you will need to travel you will need to find how far they are traveling in one hour..
To find this you will need to set up a proportion...
3/195 = 1/x
Solve this proportion by cross multiplying and then dividing..
195 * 1 = 195/3 = 65
This tells you that they are traveling 65 miles per hour. Now with this you will simply have to multiply 65 by 5 to tell you how far they would be traveling in 5 hours with the given speed...
65 * 5 = 325
Your answer of 325 miles tells you how far they traveled.
Hope it Helped!
~A
Answer:
Solution given:
slope(m)=½
passing through point (x',y')=(0,3)
now
equation of a line is:
y-y'=m(x-x')
y-3=½(x-0)
y=½x+3
<u>D</u><u>.</u><u>y</u><u>=</u><u>½</u><u>x</u><u>+</u><u>3</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>equation</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>line</u><u>.</u>
Answer:
14
Step-by-step explanation:
If he is solving 2 problems per minute and 8 minutes have passed, he has solved
2*8 = 16 problems
There are 30 problems and he has solved 16
30-16 = 14
There are 14 problems left to solve at the start of the 9th minute
Alright, lets get started.
Suppose the original square window has the side = x feet
The new window is 3 ft wider and 2 ft higher than the square one.
Means length of the new window will be = 
Width of the new window will be = 
So the area of the new window will be = 
So the area of the new window will be = 
So the area of the new window will be = 
As given in question the area of 30 square feet for the new window, hence


Factoring

x = -8 or x = 3
Side could not be negative hence
side of the original square window will be = 3 feet : Answer
Hope it will help :)
Answer:
x = 9 (it is seriously not drawn to scale)
Step-by-step explanation:
BC = DC^2 + BD^2 (Pythagorean theorem)
BC = 4^2 + 6^2
BC = 16 + 36
BC = 52^2
BC = 2sqrt13
BC/AB = DC/BD
(2sqrt13)/AB = 4/6
6(2sqrt13) = 4(AB)
12sqrt13 = 4AB
3sqrt13 = AB
AC^2 = AB^2 + BC^2 (Pythagorean Theorem)
AC^2 = (3sqrt13)^2 + (2sqrt13)^2
AC^2 = 117 + 52
AC^2 = 169
AC = 13
AD + DC = AC
AD + 4= 13
AD = 9