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almond37 [142]
2 years ago
10

David drove 135 miles in 3 hours ​

Mathematics
2 answers:
melisa1 [442]2 years ago
4 0

Answer: if you are trying to find the hourly rate it's 45/hr. If your looking for minute rate it's .75/min. If you are looking for seconds rate it's .0125/sec

Step-by-step explanation: divide 135 by 3 for hourly rate. Divide 45 by 60 for minute rate. Divide .75 by 60 to to get seconds rate.

Montano1993 [528]2 years ago
3 0

Answer: 45 miles per hour

Step-by-step explanation:

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Solve<br> x2 - 8x + 14 = 2x - 7
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Answer:

x=7, x=3

Step-by-step explanation:

             x^{2} -8x+14=2x-7

x^{2} -8x-2x+14+7=0

            x^{2} -10x+21=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x= \frac{-b\pm \sqrt{b^2-4ac}}{2a}

positive

x=\frac{-\left(-10\right)+\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=7

negative

x=\frac{-\left(-10\right)-\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=3

7 0
3 years ago
Evaluate the expression 5(8y+3r-5z) if r=3,y=5/8,and z=2
snow_lady [41]
First you plug in the missing values
5(8×5/8+3×3-5×2) = 20
3 0
2 years ago
Which of the following expressions entered into a graphing calculator will
Tanya [424]

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Step-by-step explanation:

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7, 15, 23, ...<br> Find the 41st term.
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PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
Brilliant_brown [7]

-2<em>x</em> + 6<em>y</em> = -38

3<em>x</em> - 4<em>y</em> = 32

To solve by elimination, multiply the top equation by 3 and the bottom equation by 2.

3(-2<em>x</em> + 6<em>y</em> = -38) --> -6<em>x</em> + 18<em>y</em> = -114

2(3<em>x</em> - 4<em>y</em> = 32) --> 6<em>x</em> - 8<em>y</em> = 64

Add the equations.

-6<em>x </em>+ 18<em>y</em> = -114

6<em>x</em> - 8<em>y</em> = 64

+_____________

0 + 10<em>y</em> = -50

10<em>y</em> = -50

<em>y</em> = -5

Substitute -5 for y into one of the original equations to find x.

3<em>x</em> - 4<em>y</em> = 32

3<em>x</em> - 4(-5) = 32

3<em>x</em> + 20 = 32

3<em>x</em> = 12

<em>x</em> = 4

Check work by plugging the <em>x</em>- and <em>y</em>-values into both of the original equations.

-2<em>x</em> + 6<em>y</em> = -38

-2(4) + 6(-5) = -38

-8 - 30 = 38

38 = 38


3<em>x</em> - 4<em>y</em> = 32

3(4) - 4(-5) = 32

12 + 20 = 32

32 = 32

Answer:

<em>x</em> = 4 and <em>y</em> = -5; (4, -5).

8 0
3 years ago
Read 2 more answers
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