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Effectus [21]
3 years ago
5

The length of a rectangle is 5 inches shorter than the width. What is the width of the rectangle if the perimeter is 48 inches?

Please show the equation
Mathematics
1 answer:
Setler [38]3 years ago
6 0
Perimeter = 2L + 2W  = 48                    WHERE L=length and W=width

The length must be longer than the width so im going to say that L = W + 5

so the equation is 

2(W + 5)  + 2W = 48

2W + 2W + 10 = 48

4W = 38 

W = 38/4 = 9.5 ins and  

length = 5+9.5 = 14.5 ins
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Answer:

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Step-by-step explanation:

\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}

we need to simplify that

x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)

so we can continue

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and we can put all together

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Answer:

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