Answer:
Its B and its not that hard because im doing that rn lol but do you need me to explain?
Step-by-step explanation:
Given:
The numbers are
.
To find:
All the values that cannot be probabilities.
Solution:
We know that,
![\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}](https://tex.z-dn.net/?f=%5Ctext%7BProbability%7D%3D%5Cdfrac%7B%5Ctext%7BFavorable%20outcomes%7D%7D%7B%5Ctext%7BTotal%20outcomes%7D%7D)
The minimum value of favorable outcomes is 0 and the maximum value is equal to the total outcomes. So, the value of probability lies between 0 and 1, inclusive. It other words, the probability lies in the interval [0,1].
![0\leq \text{Probability}\leq 1](https://tex.z-dn.net/?f=0%5Cleq%20%5Ctext%7BProbability%7D%5Cleq%201)
From the given values only
lie in the interval [0,1]. So, these values can be probabilities.
The values
does not lie in the interval [0,1]. So, these values cannot be probabilities.
Therefore, the correct values are
.
Answer:3x^3+6x^2+8x+24 R-47/X-2
Step-by-step explanation: