Which of the following polynomials is in standard form? (PICTURE)
1 answer:
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Answer:
(2, - 9 )
Step-by-step explanation:
Since 2 is the output when - 9 is input to f(x)
Then reversing the procedure, that is the inverse gives an output of - 9 for an input of 2.
(- 9, 2) is a point on the graph of f(x), then
(2, - 9) is a point on the graph o the inverse function (x)
If you cannot read it, let me know.
The equation is:
h ( t ) = - 16 t² + 60 t + 3
The toy rocket will reach the ground when: h ( t ) = 0
- 16 t² + 60 t + 3 = 0
t 1 = - 0.05
t 2 = 3.8
Answer:
C ) 3.80 s
h ( t ) = - 16 t² + 60 t + 3
The toy rocket will reach the ground when: h ( t ) = 0
- 16 t² + 60 t + 3 = 0
t 1 = - 0.05
t 2 = 3.8
Answer:
C ) 3.80 s
<h3>Answer: -7 < x < 17</h3>
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Explanation:
Plug in the lower bound of the domain, which is x = -3
f(x) = 3x+2
f(-3) = 3(-3)+2
f(-3) = -9+2
f(-3) = -7
If x = -3, then the output is y = -7. Since f(x) is an increasing function (due to the positive slope), we know that y = -7 is the lower bound of the range.
If you plugged in x = 5, you should find that f(5) = 17 making this the upper bound of the range.
The range of f(x) is -7 < y < 17
Recall that the domain and range swap places when going from the original function f(x) to the inverse
This swap happens because how x and y change places when determining the inverse itself. In other words, you go from y = 3x+2 to x = 3y+2. Solving for y gets us y = (x-2)/3 which is the inverse.
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In short, we found the range of f(x) is -7 < y < 17.
That means the domain of the inverse is -7 < x < 17 since the domain and range swap roles when going from original to inverse.