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Phoenix [80]
3 years ago
13

Somebody plz help on this real quick

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
6 0
★ Logarithmic Reductions ★

3 + 4 {e}^{x + 1}  = 11 \\ 4 {e}^{x + 1}  = 11 - 3 \\ 4 {e}^{x + 1}  = 8 \\  {e}^{x + 1}  = 2 \\ applying \:  log_{e} \: to \: both \: the \: sides \\x + 1 = ln2 \\ x = ln2 \:  - 1


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find the equation of the line that is parallel to y=3x-2 and contains the point (2,11), answer all boxes please
stiks02 [169]

Answer:

y = 3x+6

Step-by-step explanation:

y=3x-2

This is in the form

y = mx+b where m is the slope and b is the y intercept

The slope is 3 so a line parallel also has a slope of 3 since parallel lines have the same slope.

Using slope intercept form

y = 3x+b

We have a point (2,11)

11 = 3*2+b

11 =6+b

11-6 = b

5 =b

The equation is

y = 3x+6

4 0
3 years ago
Answer the question in the image (linear and non-linear equations, year 8, worth 30PT).
Alla [95]

Answer:

C

Step-by-step explanation:

The gradient is

\frac{2-5}{0-2}=-\frac{3}{2}

So, using the y-intercept, the equation is

y=-\frac{3}{2}x+2

6 0
1 year ago
Explain how to modify the graphs of f(x) and g(x) to graph the solution set to the following system of inequalities. How can the
Norma-Jean [14]

The graphs of f(x) and g(x) are transformed function from the function y = x^2

The set of inequalities do not have a solution

<h3>How to modify the graphs</h3>

From the graph, we have:

f(x) = x^2 -3 and g(x) = -x^2 +2

To derive y < x^2 - 3, we simply change the equality sign in the function f(x) to less than.

To derive y > x^2 + 2, we perform the following transformation on the function g(x)

  • Shift the function g(x) down by 2 units
  • Reflect across the x-axis
  • Shift the function g(x) down by 3 units
  • Change the equality sign in the function g(x) to greater than

<h3>How to identify the solution set</h3>

The inequalities of the graphs become

y < x^2 - 3 and y > x^2 + 2

From the graph of the above inequalities (see attachment), we can see that the curves of the inequalities do not intersect.

Hence, the set of inequalities do not have a solution

Read more about inequalities at:

brainly.com/question/25275758

7 0
3 years ago
1 kilometre is how much miles​
algol [13]

Answer:

1 kilometre is 0.621 mile

7 0
3 years ago
Read 2 more answers
In 1980, the median age of the U.S. population was 30.0; in 2000, the median age was 35.3.
miss Akunina [59]

Answer:

y = 0.265x - 494.7

Step-by-step explanation:

Let median age be represent by 'a' and time be represent by 't'

In 1980, median age is given 30

which means that

a₁ = 30

t₁ = 1980

In 2000, the median age is given 35.3

which means that.

a₂ = 35.3

t₂ = 2000

The slope 'm' of the linear equation can be found by:

m = (a₂ - a₁) /(t₂ - t₁)

m = (35.3 - 30)/(2000-1980)

m = 0.265

General form of linear equation is given by:

y = mx + c

y = 0.265x +c

Substitute point (1980,30) in the equation.

30 = 0.265(1980) + c

c = -494.7

Hence the the linear equation can be written as:

y = mx + c

y = 0.265x - 494.7

4 0
3 years ago
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