3 years ago

Somebody plz help on this real quick

1 answer:

6 0

★ Logarithmic Reductions ★

$3 + 4 {e}^{x + 1} = 11 \\ 4 {e}^{x + 1} = 11 - 3 \\ 4 {e}^{x + 1} = 8 \\ {e}^{x + 1} = 2 \\ applying \: log_{e} \: to \: both \: the \: sides \\x + 1 = ln2 \\ x = ln2 \: - 1$

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