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krek1111 [17]
3 years ago
9

A car that Sophia wants to buy costs $21,000. She does research and finds that after 14 years the car depreciates to a value of

zero. If the car depreciates in straight line form, write the straight line depreciation equation.
Mathematics
1 answer:
lozanna [386]3 years ago
5 0

Answer:

y=-1500x + 21000

Step-by-step explanation:

I =PRT

I = interest

P = principal

R = interest rate%

T = time

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What is the x value such that y =15 - 3x and y = 0? Please explain how you got this answer.
ICE Princess25 [194]

Answer:

x=5

Step-by-step explanation:

So how i came about to get this answer, was

y=15-3x

y=15-3(5)

y=15-15

y=0

I found five by testing out different numbers for x such as 1 2 3 4, but when i got to five, that was where i got the answer, as shown above.

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3 years ago
PUT THESE NUMBERS IN ORDER GREATEST TO LEAST ✔✔ I WILL ADD BRAINLIST
Fiesta28 [93]

Answer:

2 12/16, 2 18/25, and lastly 2.

Step-by-step explanation:

Since 2 is least, we can put that at the end. That leaves us with 2 18/25 and 2 12/16. Since 12/16 is greater, we will put that as the greatest. 2 18/25 is in the middle. Hope this helps!

6 0
3 years ago
A bacteria colony increases in size at a rate of 4.0581e1.6t bacteria per hour. If the initial population is 36 bacteria, find t
Harrizon [31]

Answer:

1560

Step-by-step explanation:

The rate of Increase of the population (P) of the bacteria is given as:

\frac{dP}{dt} =4.058e^{1.6t}

dP =4.058e^{1.6t}}dt\\Taking\: Integrals\\\int dP =4.058 \int e^{1.6t}dt\\P(t)=\frac{4.058}{1.6} (e^{1.6t} +K)\\P(t)=2.53625 (e^{1.6t} +K)

Where k is a constant of Integration.

At t=0, P(t)=36

36=2.53625 (e^{1.6*0} +K)\\36=2.53625 (e^{0} +K)\\36=2.53625 (1 +K)\\36=2.53625 +2.53625K\\K=13.19

Therefore:

P(t)=2.53625 (e^{1.6t} +13.19)\\At \: t=4\\P(4)=2.53625 (e^{1.6*4} +13.19)\\=1559.88\\P(4)=1560

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lys-0071 [83]

Answer:

A B and D

Step-by-step explanation:

4 0
3 years ago
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