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2 years ago

Please help with a math problem must show work.

Mathematics

2 answers:

jeyben [28]2 years ago

8 0

Correct answer: (B) C/2r=pi

Burka [1]2 years ago

5 0

Answer:

Step-by-step explanation:

you watch you Tube

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Pattern: 0, 1, 3, 6, 10, 15, __<br> Explain the pattern of these numbers.

chubhunter [2.5K]

Answer:

Step-by-step explanation:

0 + 1 = 1

1 + 2 = 3

3 + 3 = 6

6 + 4 = 10

10 + 5 = 15

15 + 6 = 21

Each number is added to an increase of 1 - first add 1, then add 2, then add 3,etc

Not listed but next would be 21 + 7 = 28

so it would be 0, 1, 3, 6, 10, 15, 21, 28

5 0

3 years ago

The length of the rectangle is one units more than the width. The area of the rectangle is 56 units. What is the width, and unit

-Dominant- [34]

Width is x.

Length is (x + 1).

Area = length*width

56 = x(x+1)

x² + x - 56 = 0

(x+8)(x-7)=0

x = - 8, or x = 7

"- 8" is impossible for width.

So, width x = 7

Length = (x+1) = 7+1 = 8

6 0

2 years ago

Students attending the University of Florida can select from 130 major areas of study. A student's major is identified in the re

omeli [17]

Answer:

1. 8385 double majors

2. 18252 major codes

3. 8515 codes

4. Yes

Step-by-step explanation:

Given

Major areas = 130

Alphabets = 26

There are 130 major areas in the university.

To get a double majors, means one select any of two of the major areas in the university.

i.e. just 2 alphabets are needed

Number of Double Majors = 130C2

130C2 = 130!/(128!*2!)

130C2 = 130 * 129/2

130C2 = 8385.

Number of major codes available = Number of 2 digit codes + Number of 3 digit codes

Number of 2 digit codes = 2 alphabets

There are 26 ways of selecting the first letter

There are 26 ways of selecting the second letter

So, number of 2 digit codes = 26 * 26 = 676.

Number of 3 digit codes = 3 alphabets

There are 26 ways of selecting the first letter

There are 26 ways of selecting the second letter

There are 26 ways of selecting the third letter

So, number of 3 digit codes = 26 * 26 * 26 = 17576

Thus, number of major codes = 17576 + 676 = 18252

Number of codes to identify a student with either a single major or double major

Number off single major codes = number of major areas = 130

Number of double major codes = 8385

Total = 130 + 8385 = 8515

d. From the solutions above, Yes there are enough codes available to identify all single and double majors at the university

6 0

2 years ago

Don has two jobs for job 1 he earns 7.55 an hour. For job 2 he earns 8.45 an hour last week he worked at the first job for 10 ho

Crazy boy [7]

Answer:

for the first job is $75.05 and for the second job is $126.75

8 0

3 years ago

Find the missing length. The triangles in each pair are similar.

oee [108]

Answer:

Step-by-step explanation:

This a not so simple ratio problem:

MN is to LN as TN is to UN as MT is to LU

MN/LN = TN/UN = MT/ LU trying to find LU

88 / (? + 32) = (88-56)/32 = 56/?

= 32 / 32 = 56 / ?

1 = 56 / ?

? = 56

88 / (56 +32) = 1 This must be an Isosceles triangle and UT bisects

LN and MN

5 0

2 years ago