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attashe74 [19]
2 years ago
14

Simplify to a single power of 4:4² x 4

Mathematics
1 answer:
Charra [1.4K]2 years ago
4 0

Answer:

64

Step-by-step explanation:

4^{2} . 4 = 4^{3} = 4.4.4

=> 4x4x4=16x4=64

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The graph of a polynomial S(x) = (2x - 3)(x – 4)(x+3) has x-intercepts at 3.x values.
dezoksy [38]

Answer:

Step-by-step explanation:

x-intercepts exist where y is equal to 0. Where y is equal to 0 is where the graph goes through the x-axis. Our x-intercepts are (2x-3), (x + 3), and (x-4). Again, since x-intercepts exist where y = 0, then by the Zero Product Property, 2x - 3 = 0, x - 4 = 0, and x + 3 = 0. In the first x-intercept:

2x - 3 = 0 and

2x = 3 so

x = 3/2

In the second:

x - 4 = 0 so

x = 4

In the third:

x + 3 = 0 so

x = -3

So the x-intercepts in the correct order are x = 3/2, 4, -3

6 0
3 years ago
Please help i have no idea what it means and the test is tomorrow.
Anarel [89]

Answer:

H. 2

Step-by-step explanation:

√(1 − cos² x) / sin x + √(1 − sin² x) / cos x

Use Pythagorean identity.

sin² x + cos² x = 1

So:

1 − cos² x = sin² x

and

1 − sin² x = cos² x

Substitute:

√(sin² x) / sin x + √(cos² x) / cos x

sin x / sin x + cos x / cos x

1 + 1

2

8 0
3 years ago
Greg borrowed $100 from his parents. After he did some chores, they reduced the amount of his debt by $25.
Mariana [72]

Answer:

6. ,!,,,,,,,,,,,,,,,,,,,,,,,,mmm,m,,,mmm,,,,,,,,,,,,

3 0
3 years ago
Could someone please simplify for me the square root of 4312?? I would really appreciate it.
stepan [7]
Square root of 4312 = 65.66582064
3 0
3 years ago
A boat traveled 210 miles downstream and back. The trip downstream took 10 hours. The trip back took 70 hours. What is the speed
musickatia [10]

Try this solution:

Answer: 6 & 4.5 (m-per-h)

Step-by-step explanation:

- The basic formula used in this task is S=V*t, where S - distance, V - speed, t - time.

- the downstream speed is: V+Vc, where V - the speed of the boat in still water, Vc - the speed of the current.

- the upstream speed is: V-Vc.

- according to the described above the distance for downstream is S1=(V+Vc)*t1, where t1=10; the distance for upstream is S2=(V-Vc)*t2, where t2=70.

- for whole travel down- and upstream: S=S1+S2.

- Using these it is possible to make up the system of the equations:

\left \{ {{(70(V-V_c)=10(V+V_c)} \atop {70(V-V_c)+10(V+V_c)=210}} \right.

V - the speed of the boat in still water - 6 miles per hour, Vc - the speed of the current - 4.5 miles per hour. All the details for the system of the equations are in the attachment.

4 0
3 years ago
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