Answer:
f(3π/4) = -π
A = π
b = 2
Step-by-step explanation:
Given that the function follows the form: f(x) = A sin(bx), then f(0) = 0. Given that the period is π, then at x = π/4 the function reaches a maimum, at x = π/2, f(x) = 0, and at x = 3π/4, f(x) reaches a minimum, which have to be π*(-1) = -π
Given the general equation: f(x) = A sin(bx), its period is calculated as:
period = 2π/b
which is equal to π, then:
2π/b = π
b = 2
Replacing x = π/4 into the equation of the function, we get:
A sin(2(π/4)) = π
A sin(π/2) = π
A = π
Answer:
x^2 +2x +4
x^2 +2x +(2/2)^2-(2/2)^2+4
(x+1)^2-1+4
(x+1)^2+3=0
(x+1)^2= -3
(x+1)= ±√-3
Since a negative number cannot be square rooted,
there are no solutions to this equation.
Hope this helps:)
X is 9 Y is 3 and Z is 12
Answer:
m
=
−
2
Step-by-step explanation:
