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4 years ago

13

Find the shaded area of the basketball court to the nearest foot.

1 answer:

Trava [24]4 years ago

5 0

So the image consists of 1 rectangle and half a circle.
Rectangle - 12*19 = 228Half a circle - $\pi r^2 = \pi 6^2 = 36 \pi /2 = 18 \pi$
In the end there are 2 rectangles (2*228 = 456) and 1 full circle (18*2 = 36), which makes the shaded area 456ft and 36 $\pi$

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Plz help me with this question!

mart [117]

Answer:

Coefficients are 2, 5, -1. (Coefficients are the numbers before the x)

Constant is 3 (constant is the number without any x)

2x^5+0x^4+5x^3+0x^2-x+3

You start with the biggest and end with the smallest, if anything isnt present int he original equation (for example x^4 in this case) put it in with a zero before it.

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3 years ago

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romanna [79]

B

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3 years ago

Find the area and perimeter

Arada [10]

Answer:

A = 31.36

P = 22.4

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3 years ago

Read 2 more answers

Translate the sentence into an equation. Four times the difference of a number and 5 is 24.

givi [52]

$4\ times\to4\times\\difference\ of\ a\ number\ "c"\ and\ 5\to c-5\\is\ equal\ 24\to=24\\\\4\times(c-5)=24\\\\Answer:\boxed{a.}$

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4 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago