Ask question

Ask question

All categories

3 years ago

10

Movies Unlimited charges $2 per movie plus $3 per game for rentals on Saturday’s only. If you rent 4 games and you have $20, whi

ch equation could help you to figure out how many movies you can rent?

1 answer:

lana66690 [7]3 years ago

3 0

I think you would’ve rented 4 movies and 4 games

You might be interested in

I need the answer how to do

IrinaVladis [17]

Make a bar graph about the length of letters in an animal's name

5 0

3 years ago

Evaluate the expression9!/3!

Ne4ueva [31]

The answer to 9!/3! Is 60480

7 0

3 years ago

Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}

miskamm [114]

Answer:

$-3+i\sqrt{3} , 1+\sqrt{3}$

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

$\alpha = x+iy\\\beta = x-iy$

since they are conjugates

$\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}$

$\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}$

Imaginary part of the above =0

i.e. $\sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1$

So the value of alpha = $-3+i\sqrt{3} , 1+\sqrt{3}$

3 0

3 years ago

Please help me. I need how to do the problem too

MatroZZZ [7]

Answer: Choice A. (8, 4)

==========================================================

Explanation:

Because x = 2y, we can replace every copy of x with 2y

Let's do so in the second equation

3x - 4y = 8

3(x) - 4y = 8

3(2y) - 4y = 8 .... x replaced with 2y; now let's isolate y

6y - 4y = 8

2y = 8

y = 8/2 ..... divide both sides by 2

y = 4

Use this y value to find x

x = 2y

x = 2*4

x = 8

So we have x = 8 and y = 4 pair together to get the answer (x,y) = (8, 4) which is choice A.

5 0

3 years ago

Supplementary angles. If m

Olegator [25]

Answer:

Jouc ÷4 i for number 69263

hope it helps

3 0

2 years ago