Check the picture attached
let the rays forming angle T be ray 1 and ray 2
Draw a circle with center point T. Let the intersection of the circle with rays 1 and 2 be at points A and B respectively.
Draw 2 circles with centers A and <span>B so that:
The radii (radius'es) are equal, and they are large enough to intersect.
Denote the intersection of these 2 circles with C.
Join T to C. The line through T and C is the bisector.</span>
Answer:
C. it's 6 3/4 (6.75)
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feel free to give me brainliest you don't have to though
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2 x 2 x 2 x 3 x 5 is the prime factorization of 120
What are the answer choices?
Answer:
17.32m ; 110°
Step-by-step explanation:
Distance between X and Z
To calculate the distance between X and Z
y^2 = x^2 + z^2 - (2xz)*cosY
x = 20, Z = 10
y^2 = 20^2 + 10^2 - (2*20*10)* cos60°
y^2 = 400 + 100 - (400)* 0.5
y^2 = 500 - 200
y^2 = 300
y = sqrt(300)
y = 17.32m
Bearing of Z from X:
Using cosine rule :
Cos X = (y^2 + z^2 - x^2) / 2yz
Cos X = (300 + 100 - 400) / (2 * 20 '*10)
Cos X = 0 / 400
Cos X = 0
X = cos^-1 (0)
X = 90°
Bearing of Z from X
= 20° + X
= 20° + 90°
= 110°