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horrorfan [7]
3 years ago
9

I need help with some math problems, thank you​

Mathematics
1 answer:
natulia [17]3 years ago
6 0

Answer: segundo

Step-by-step explanation:

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An oral liquid concentrate of sertraline hydrochloride (Zoloft) contains 20 mg/mL of the drug. How many grams of sertraline hydr
Rzqust [24]

Answer:

1.2 grams.

Step-by-step explanation:

We have been given that an oral concentrate of sertraline hydro-chloride (Zoloft) contains 20 mg/mL of the drug.

First of all, we will find number of mg in 60 mL container of the concentrate as:

\frac{\text{20 mg}}{\text{ml}}\times \text{60 ml}

\text{20 mg}\times 60

\text{1200 mg}

We know 1 gram equals 1000 mg.

\text{1200 mg}\times \frac{\text{1 gram}}{\text{1000 mg}}

1.2\times\text{1 gram}

1.2\text{ grams}

Therefore, 1.2 grams of sertraline hydrochloride are in each 60-mL container of the concentrate.

3 0
3 years ago
What are the next two numbers in this pattern?
disa [49]
The answer is A. 243, -729

The pattern of this is that they multiply each number by -3.

3*-3=-9
-9*-3=26
27*-3=-81

So you have to multiply -81 by -3. Then multiply that by -3 to get the second number

-81*-3=243
243*-3=-729
3 0
3 years ago
What are his numbers sin, tan, cos, pi, and Square roots
nydimaria [60]

Answer:

The value of pi is equal to 3.14

7 0
3 years ago
Read 2 more answers
Hi guys this is my question
sasho [114]

Answers -

statement B, D, E are correct .

Solution -

As figure B is the scaled copy of figure A, so it is smaller than B and its perimeter is also less than that of A.

On the other hand , as B is the smaller replica of A, so it has same number of edges ,angels and sides. Though the length of the sides are not same, the angels are same. so the perimeters of both figures are different but sum of all the angels are same.

5 0
3 years ago
I have 30 ones, 82 thousands, 4 hundred thousands, 60 tens, and 100 hundreds. What number am I?
stich3 [128]
This problem tackles the place values of numbers. From the rightmost end of the number to the leftmost side, these place values are ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, one hundred millions, and so on and so forth. My idea for the solution of this problem is to add up all like multiples. In this problem, there are 5 multiples expressed in ones, thousands, hundred thousands, tens and hundreds. Hence, you will add up 5 like terms. The solution is as follows

30(1) + 82(1,000) + 4(100,000) + 60(10) + 100(100)

The total answer is 492,630. Therefore, the number's identity is 492,630.
7 0
3 years ago
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