Answer:
yes your answer is correct
Step-by-step explanation:
Answer:
In general, quadratic equations have two x-intercepts. But sometimes it happens that a quadratic eqution has one x-intercept or no interepts. That's why we should fully analyze this equation:
Given the following equation: y=3x^2 + 7 + m
If y=0, then:
3x^2 + 7 + m = 0 ⇒ x^2 = (-m-7)/3
Then
± ![\sqrt{\frac{-m-7}{3}}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B-m-7%7D%7B3%7D%7D)
Given that we can take the square root of a negative number, the only way this equation has two x-intercepts is if m<-7.
Summarizing:
The equation: y=3x^2 + 7 + m has two x-intercepts only if m is less than -7. If m equals -7, the equation has only one x-intercept, and finally, if m is greater than -7, the equation has NO x-intercepts.
Answer:
C
Step-by-step explanation:
The picture
You can get this answer bye dividing the two numbers
9.125×10^2÷9.125×10^-3
Cancel the 9.125 to 9.125 and u will remind with 10^2÷10^-3
Exponent divided by exponent.
2-(-3)=5
10^5=100,000
9.125×10^-3 is 100,000 times less than 9.125×10^2
I think it will help
8 in the first box , 16 in the one next to it