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4 years ago

If a rectangle has a base of 6 units, and a height of 8 units, what is its area?

Mathematics

2 answers:

Lapatulllka [165]4 years ago

8 0

The area of the rectangle is 48 units

Morgarella [4.7K]4 years ago

4 0

Answer:

a=48 units^2

Step-by-step explanation:

The area of a rectangle can be found using:

a=bh

We know the base is 6, and the height is 8, so we can substitute them in

a=6*8

a=48

Area uses units squared, so,

a=48 units^2

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3 years ago

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). A construction

charle [14.2K]

Answer:

$y=\frac{11}{20}x+6$

Step-by-step explanation:

Given:

Two points are given

x = number of minutes

y = length of the lin

$(x_{1},y_{1} )$ ⇒ (0, 6)

$(x_{2},y_{2} )$ ⇒ (20, 17)

We need to find the equation that represents the relationship between x, y.

Solution:

Using slope formula to find the slope of the equation of the line.

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute $(x_{1},y_{1} )$ = (0, 6) and $(x_{2},y_{2} )$ = (20, 17) in above equation.

$m=\frac{17-6}{20-0}\\m=\frac{11}{20}$

So, slope of the line $m = \frac{11}{20}$

Using point slope formula.

$(y-y_{1})=m(x-x_{1})$ ------------(1)

Where, m = slope of the line

Substitute $(x_{1},y_{1} )$ ⇒ (0, 6) and $m = \frac{11}{20}$ in equation 1.

$(y-6)=\frac{11}{20} (x-0)$

$y-6=\frac{11}{20}x$

Add 6 both side of the equation.

$y-6+6=\frac{11}{20}x+6$

$y=\frac{11}{20}x+6$

Therefore, the equation that represents the relationship between x and y is written as:

$y=\frac{11}{20}x+6$

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4 years ago

Using the image prove its shape.

Vladimir79 [104]

The shape is a parallelogram because the length of the sides based on the coordinates

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3 years ago

Determine g(x + a) – g(x) for the following function.<br> g(x) = 5x2 + 2x

dusya [7]

Answer:

$g(x + a) - g(x) = 10ax + 5a^2 + 2a$

Step-by-step explanation:

We are given the function:

$g(x) = 5x^2 + 2x$

And we want to determine:

$\displaystyle g(x+a) - g(x)$

Substitute:

$\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \end{aligned}$

And simplify:

$\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \\ \\ &= \left(5(x^2 + 2ax + a^2) + (2x + 2a) \right) + \left(-5x^2 - 2x\right) \\ \\ &= \left((5x^2 + 10ax + 5a^2) + (2x + 2a)\right) + \left(-5x^2 - 2x\right) \\ \\ &= (5x^2-5x^2) + (10ax + 2x - 2x) + (5a^2+2a) \\ \\ &= 10ax + 5a^2 + 2a \end{aligned}$

In conclusion:

$g(x + a) - g(x) = 10ax + 5a^2 + 2a$

3 0

3 years ago