Answer:
2. congruent
3. congruent
Step-by-step explanation:
Segments will be congruent if their lengths are the same. Their lengths will be the same if the sum of squares of the x- and y-differences of their endpoint coordinates are the same.
2. B-A = (-4-(-4), 8-1) = (0, 7)
D-C = (5-(-2), -5-(-5)) = (7, 0)
The total of 0² and 7² is the same as the total of 7² and 0², so these segments are congruent. (They are both of length 7.)
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3. B-A = (2-4, 6-1) = (-2, 5)
D-C = (-4-(-2), -3-2) = (-2, -5)
The sum of (-2)² and 5² is the same as the sum of (-2)² and (-5)², so these segments are congruent. (They both are of length √29.)
Xy + 6e^y = 6e
taking first derivative :
<span>xy' + y + 6y(e^y)(y') = 0 </span>
<span>xy" + y' + y' + 6y'(e^y)(y') + 6yy(e^y)y' + 6y(e^y)y" = 0 </span>
<span>Put x = 0,
0 + 6e^y = 6e,
y = 1 </span>
<span>0 + 1 + 6(1)(y')e = 0,
Put y' = 0 </span>
<span>0 + 0 + 0 + 0 + 0 +6 ey" = 0,
y" = 0</span>
Answer: 4 and 5/18
Step-by-step explanation: In this problem, we have 7/6 divided by 3/11. Dividing by a fraction is the same as multiplying by its reciprocal. In other words, we can change the division sign to multiplication and flip the second fraction.
So here, 7/6 ÷ 3/11 can be rewritten as 7/6 × 11/3.
Now we are simply multiplying fractions so we multiply across the numerators and multiply across the denominators.
So we have 7 × 11 which is 77 and 6 × 3 which is 18.
Now we have the fraction 77/18.
We can write 77/18 as a mixed number by dividing the denominator of the fraction into the numerator.
18 divides into 77 4 times with a remainder of 5.
So we can write 77/18 as 4 and 5/18.
Notice that the 18 stays which is the denominator of our original answer.
This means that 7/6 ÷ 3/11 = 4 and 5/18.
Answer:
B
Step-by-step explanation:
We have perpendicular bisector through a chord of the circle. We know the length, so either side of the chord is 11 due to the bisector cutting it directly in half. Since the radius is a fixed distance from the center to any point on the edge of the circle, we can draw the radius x from the circle to the end of the chord to form a right triangle.
We can use Pythagorean Theorem 
to find the missing side length x. a=6, b=11 and c=x.
Hi there! It's b hope this helps!
